Hello!
The angle is a right angle, which measures 90°.
3x + x = 4x
Angle = 4x + 10 = 90
Switch that around
90 - 10 = 4x
90 - 10 = 80
80 = 4x
Divide by 4
]
Answer:
392
Step-by-step explanation:
Answer:
The launch angle should be adjusted to 30.63°
Step-by-step explanation:
The range of a projectile which is the horizontal distance covered by the projectile can be expressed as;
R =(v^2 sin2θ)/g
Where
R = range
v = initial speed
θ = launch angle
g = acceleration due to gravity
For the case above. When the projectile is launched at angle 13° above the horizontal.
θ1 = 13
R1 = (v^2 sin2θ1)/g
R1 = (v^2 sin26°)/g ....1
For the range to double
R2 = (v^2 sin2θ)/g .....2
R2 = 2R1
Substituting R2 and R1
(v^2 sin2θ)/g = 2 × (v^2 sin26°)/g
Divide both sides by v^2/g
sin2θ = 2sin26
2θ = sininverse(2sin26)
θ = sininverse(2sin26)/2
θ = 30.63°
Step-by-step explanation:
B) the sum of 3 times a number and 4
Hope it's helpful to you
Answer:
.
Step-by-step explanation:
The given expression is
It can be rewritten as
![2\left [\pi-\cos^{-1}\left(\frac{1}{\sqrt{2}}\right)\right]](https://tex.z-dn.net/?f=2%5Cleft%20%5B%5Cpi-%5Ccos%5E%7B-1%7D%5Cleft%28%5Cfrac%7B1%7D%7B%5Csqrt%7B2%7D%7D%5Cright%29%5Cright%5D)
![[\because \cos^{-1}(-x)=\pi-\cos^{-1}(x), x\in [-1,1]]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Ccos%5E%7B-1%7D%28-x%29%3D%5Cpi-%5Ccos%5E%7B-1%7D%28x%29%2C%20x%5Cin%20%5B-1%2C1%5D%5D)
![2\left [\pi-\cos^{-1}\left(\cos \frac{\pi}{4}\right)\right]](https://tex.z-dn.net/?f=2%5Cleft%20%5B%5Cpi-%5Ccos%5E%7B-1%7D%5Cleft%28%5Ccos%20%5Cfrac%7B%5Cpi%7D%7B4%7D%5Cright%29%5Cright%5D)
![2\left [\pi-\frac{\pi}{4}\right]](https://tex.z-dn.net/?f=2%5Cleft%20%5B%5Cpi-%5Cfrac%7B%5Cpi%7D%7B4%7D%5Cright%5D)
![2\left [\frac{4\pi-\pi}{4}\right]](https://tex.z-dn.net/?f=2%5Cleft%20%5B%5Cfrac%7B4%5Cpi-%5Cpi%7D%7B4%7D%5Cright%5D)
Hence, the exact value of given expression is .
