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koban [17]
4 years ago
11

Researchers discovered a strain of C. parvum that expresses a functional variation of the lactate dehydrogenase gene. A DNADNA s

equence comparison showed that the variant differs from the normal sequence in the region that codes for the enzyme’s allosteric site. Predict the effect of FX11FX11 treatment on C. parvum cells that express this variant of lactase dehydrogenase. Provide reasoning to support your prediction. Explain how gossypol and FX11FX11 might be used as drugs to treat C. parvum infections in humans without negatively affecting human cells.

Biology
1 answer:
allsm [11]4 years ago
4 0

Answer:

the question is incomplete, the graph is attached and the requested question is answered

The affinity of the inhibitor will be affected when the allosteric site is affected or changed, for which more information is required, however the change will reduce the affinity and the FX11 structure will not be effective when inhibiting the growth of C. parvum, an inhibitor it can return to the allosteric site since it contains characteristics that allow it to mate, however if these structures change their conformation, the inhibitor will not be able to bind and the affinity will decrease.

This system can be used to generate medications, however the pathway by which the parasite is going to attack interrupts the lactic fermentation and is located in the digestive system of the nospedero, in these organs there is a decrease in aerobic respiration, in these conditions it is can affect muscle tissue, so one of the recommendations is to avoid physical activity while taking the drugs

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Calculate the mass of glucose metabolized by a 78.8 kg person in climbing a mountain with an elevation gain of 1570 m . Assume t
bearhunter [10]

Answer:

The mass of glucose metabolized by a 78.8 kg person in climbing a mountain with an elevation gain of 1570 m, is 311.5 grams

Explanation:

Step 1: Data given

Mass of the person = 78.8 kg

elevation = 1570 meters

Molar mass of glucose = 180.16 g/mol

Standard enthalpy of combustion of glucose = -2805 kJ/ mol

Step 2:

W = m*g*h

with m = mass of the person in kg = 78.8 kg

with g = acceleration due to gravity = 9.81 m/s²

with h = height in meters = 1570 meters

W = 78.8 * 9.81 * 1570 = 1213653.96 J = 1.213 *10^6 J

Step 3: Calculate actual work

Actual work = 4W = 4.85 *10^6 J = 4.85 *10³ kJ

Step 4: Calculate moles glucose

Moles glucose = work / standard enthalpy

Moles glucose = 4.85 *10³ kJ / 2805 kJ/mol = 1.729 moles

Step 5: Calculate mass of glucose

Mass glucose = moles glucose * Molar mass glucose

Mass glucose = 1.729 moles * 180.16 g/mol

Mass glucose = 311.5 grams

The mass of glucose metabolized by a 78.8 kg person in climbing a mountain with an elevation gain of 1570 m, is 311.5 grams

8 0
4 years ago
Explain how soil structure affects the physical properties of soil
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Answer:

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You are a teaching assistant for an introductory biology laboratory. you would like your students to see connections between adm
guajiro [1.7K]

The correct answer is skeletal development resulting in the movement of amphibians onto land and possibly evolved from lobe-finned fishes.

The initial lobe-finned fishes are bony fish with lobed, fleshy, paired fins that are connected with the body by a solitary bone. The fins of the lobe-finned fishes vary from those of all other fish in that each is borne on a lobe like, fleshy, scaly stalk protruding from the body.

This skeletal development will show that the species first developed in water and then gradually move onto the land and ultimately developed as species of land.

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Given the age of the meteorite is 4.5 billion years old with 78 atoms of lead-206 the answer should be B. 156. The half-life of uranium-238 in order to decay into lead-206 is 4.46 billion years, which means that the original number of atoms is 156.  
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