Answer:
my=(1/5 , 1/5, 2/5 , 1/5) for Y=(2,3,4,5)
mz=(1/5 , 3/5, 1/5 ) for Z=(0,1,4)
Step-by-step explanation:
for Y
for X=(-1) , Y= -1+3=2 , my=mx=1/5 → my(Y=2)=1/5
for X=0 , Y= 0+3=3 , my=mx=1/5 → my(Y=3)=1/5
for X=1 , Y= 1+3=4 , my=mx=2/5 → my(Y=4)=2/5
for X=2 , Y= 2+3=5 , my=mx=1/5 → my(Y=5)=1/5
for Z
for X=(-1) ,Z= (-1)²=1 , mz [X=(-1)]=mx=1/5
for X=0 ,Z= 0²=0 , mz=mx=1/5 → mz(Z=0)=1/5
for X=1 ,Z= 1²=1 , mz [X=1]=mx=2/5 → mz(Z=1)= 1/5+ 2/5 = 3/5
for X=2 ,Z= 2²=4 , mz=mx=1/5 → mz(Z=4)=1/5
