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3 years ago

Pleas help please hurry please thank u!!!!!!

Mathematics

2 answers:

USPshnik [31]3 years ago

8 0

The answer will be 8/43 or 0.1860465116

lukranit [14]3 years ago

7 0

8 students prefer non-fiction of the 43 9th grader students.
8/43 = 0.18604
Rounded: 0.19

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all you need to do is change your percentages to decimal and then multiply

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3 years ago

Pls help me

Aneli [31]

Answer:

The answer would be 15. Your welcome my good sir

Step-by-step explanation:

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2 years ago

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Anika [276]

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3 years ago

Product A requires 5 machine hours per unit to be produced, Product B requires only 3 machine hours per unit, and the company's

Lesechka [4]

Answer:

Produce only Product B.

Step-by-step explanation:

The contribution margin per machine hour for product A is ...

($16 -$6)/(5 hour) = $2 per hour

The contribution margin per machine hour for product B is ...

($12 -$5)/(3 hour) ≈ $2.33 per hour

The company should produce the maximum possible number of the product that contributes the most per machine hour: Product B.

5 0

3 years ago

Please help ASAP! Thanks! For the figures below, assume they are made of semicircles, quarter circles and squares. For each shap

bazaltina [42]

Answer:

Part 1) $A=36(\pi-2)\ cm^2$

Part 2) $P=6(\pi+2\sqrt{2})\ cm$

Step-by-step explanation:

Part 1) Find the area

we know that

The area of the shape is equal to the area of a quarter of circle minus the area of an isosceles right triangle

$A=\frac{1}{4}\pi r^{2}-\frac{1}{2}(b)(h)$

we have that the base and the height of triangle is equal to the radius of the circle

$r=12\ cm\\b=12\ cm\\h=12\ cm$

substitute

$A=\frac{1}{4}\pi (12)^{2}-\frac{1}{2}(12)(12)$

$A=(36\pi-72)\ cm^2$

simplify

Factor 36

$A=36(\pi-2)\ cm^2$

Part 2) Find the perimeter

The perimeter of the figure is equal to the circumference of a quarter of circle plus the hypotenuse of the right triangle

<em>The circumference of a quarter of circle is equal to</em>

$C=\frac{1}{4}(2\pi r)=\frac{1}{2}\pi r$

substitute the given values

$C=\frac{1}{2}\pi (12)$

$C=6\pi\ cm$

The hypotenuse of right triangle is equal to (applying the Pythagorean Theorem)

$AC=\sqrt{12^2+12^2}$

$AC=\sqrt{288}\ cm$

simplify

$AC=12\sqrt{2}\ cm$

Find the perimeter

$P=(6\pi+12\sqrt{2})\ cm$

simplify

Factor 6

$P=6(\pi+2\sqrt{2})\ cm$

6 0

3 years ago