36 equally-likely outcome: (1,1), (1,2), (1,3), (1,4), (1,5), (1,6), (2,1), (2,2), (2,3), (2,4), (2,5), (2,6), (3,1), (3,2), (3,3), (3,4), (3,5), (3,6), (4,1), (4,2), (4,3), (4,4), (4,5), (4,6), (5,1), (5,2), (5,3), (5,4), (5,5), (5,6), (6,1),(6,2), (6,3), (6,4), (6,5), (6,6)
Solution:
Outcomes with first number being old number and second being even number: (1,2), (1,4), (1,6), (3,2), (3,4), (3,6), (5,2), (5,4), (5,6) = 9 outcomes
P(old,even) = 9/36 =1/4 = 0.25
What you must do for this case is to see the percentage in each of the cases in order to have a point of comparison.
We have then:
44 people of 230:
(44/230) * (100) = 19.13%
Of women, 26 out of 112:
(26/112) * (100) = 23.21%
answer:
Your company was more highly rated among the
B) Women
Answer:
Step-by-step explanation:
Given
Required
Rewrite to remove fractions
The denominators in the above expression are 4 and 6.
So, first we take the LCM of 4 and 6
Next, multiply both sides of the equation by this LCM (12)
Answer:
6-hours
D = C + T
Step-by-step explanation:
The following equations represent the total distance travelled by each vehicle, the truck (C) and the Train (T) where x is the amount of time travelling in hours...
C = 45x
T = 60x
Since the truck traveled 2 hours longer than the train we can add this value to the variable x in the truck's distance equation and then make both equations equal one another to calculate the number of hours before they cover the same distance...
45(x+2) = 60x ... distribute 45 evenly
45x + 90 = 60x ... subtract 45x from both sides
90 = 15x ... divide both sides by 15
6 = x
Finally, we can see that both vehicles would have traveled the same distance at the 6-hour mark. Now to calculate the total distance traveled (D) we can use the following equation...
D = C + T
