Question

Point X is located at (3,2). Point Y is located at (3,−8).

Answer 1

Answer:

$d=10\ units$

Step-by-step explanation:

we know that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

$X(3,2)\\Y(3,-8)$  

substitute the values

$d=\sqrt{(-8-2)^{2}+(3-3)^{2}}$

$d=\sqrt{(-10)^{2}+(0)^{2}}$

$d=\sqrt{100}$

$d=10\ units$