Question

6. If the equations kx - y = 2 and 6x - 2y = 3 have a solution then state the value of k a) K = 3 b) k 3 c ) K 0 d) k = 0 7.

Answer 1

Answer:

k ≠ 3

Step-by-step explanation:

Given the system of equation;

kx - y = 2 ------------------- 1

6x - 2y = 3 -------------------- 2

Rewriting the equations in the format ax+by+c = 0

Equation 1 becomes kx - y - 2 = 0

Equation 2 becomes 6x - 2y - 3 = 0

where a₁ = k, b₁ = -1 and c₁ = -2  and a₂ = 6, b₂ = -2 and c₂ = -3

For the system of equation to have a unique solution the following must be true;

a₁/a₂ ≠ b₁/b₁

Substituting the coefficients into the condition, we will have;

k/6 ≠ -1/-2

k/6 ≠ 1/2

Cross multiplying we will have;

2k ≠ 6

k ≠ 6/2

k ≠ 3

This means that k can be any other real values except 3 for the system of equation to have a unique solution.