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3 years ago

15x-3y=96 in slope intercept form

2 answers:

5 0

<span>15x-3y=96
Subtract 15x from both sides
-3y= -15x + 96
Divide both sides by -3
Final Answer: y = 5x - 32</span>

g100num [7]3 years ago

3 0

The answer is: y=5x-32

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Juan read 300 pages in 5 days which reading rate is equivalent

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600 pages in 10 days

Step-by-step explanation:

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3 years ago

What is 0.273 to 2 decimal places

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Suppose a normal distribution has a mean of 38 and a standard deviation of

lawyer [7]

C is the right answer

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3 years ago

Solve the system of equations by using the inverse of the coefficient matrix of the equivalent matrix equation.

Alinara [238K]

The solution for the given system of equations x + 8y = -37, 4x + 8y = -52 is $\left[\begin{array}{ccc}&5&\\\\&4&\end{array}\right]$

Given,

System of equations as,

x + 8y = -37

4x + 8y = -52

We have to solve this by using the inverse of coefficient matrix of the equivalent matrix equation.

That is,

$A=\left[\begin{array}{ccc}a&&b\\\\c&&d\end{array}\right]$

$A^{-1} =\frac{1}{ad -bc} \left[\begin{array}{ccc}d&&-b\\\\-c&&a\end{array}\right]$

Now we can solve the equations.

Here we have,

x + 8y = -37

4x + 8y = -52

Now in matrix form,

$\left[\begin{array}{ccc}1&&8\\\\4&&8\end{array}\right]$ $\left[\begin{array}{ccc}&x&\\\\&y&\end{array}\right]$ $=\left[\begin{array}{ccc}&-37&\\\\&-52&\end{array}\right]$

A X B

We know that,

$A^{-1} =\frac{1}{ad -bc} \left[\begin{array}{ccc}d&&-b\\\\-c&&a\end{array}\right]$

Therefore,

$A^{-1} = \frac{1}{(1X8)-(4X8)} \left[\begin{array}{ccc}8&&-8\\\\-4&&1\end{array}\right]$

$=\frac{1}{8-32} \left[\begin{array}{ccc}8&&-8\\\\-4&&1\end{array}\right]$

$=\frac{1}{-24} \left[\begin{array}{ccc}8&&-8\\\\-4&&1\end{array}\right]$

$=\left[\begin{array}{ccc}\frac{-8}{24} &&\frac{8}{24} \\\\\frac{4}{24} &&\frac{-1}{24} \end{array}\right]$

Then,

$\left[\begin{array}{ccc}&x&\\\\&y&\end{array}\right] =$ $=\left[\begin{array}{ccc}\frac{-8}{24} &&\frac{8}{24} \\\\\frac{4}{24} &&\frac{-1}{24} \end{array}\right]$ $\left[\begin{array}{ccc}&\frac{37}{52} &\\\\\end{array}\right]$

$=\frac{1}{24} \left[\begin{array}{ccc}-8&&8\\\\4&&-1\end{array}\right]$ $\left[\begin{array}{ccc}&\frac{37}{52} &\\\\\end{array}\right]$

$=\frac{1}{24} \left[\begin{array}{ccc}(-8X37)+(8X52)\\\\(4X37)+(-1X52)\end{array}\right]$

$=\frac{1}{24} \left[\begin{array}{ccc}-296+416\\\\148-52\end{array}\right]$

$=\frac{1}{24} \left[\begin{array}{ccc}120\\\\96\end{array}\right]$

$=\left[\begin{array}{ccc}\frac{120}{24} \\\\\frac{96}{24} \end{array}\right]$

$=\left[\begin{array}{ccc}5\\\\4\end{array}\right]$

That is $\left[\begin{array}{ccc}x\\\\y\end{array}\right] =\left[\begin{array}{ccc}5\\\\4\end{array}\right]$

Learn more about matrix equations here: brainly.com/question/27799804

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The question is incomplete. Completed question is given below:

Solve The System Of Equations By Using The Inverse Of The Coefficient Matrix Of The Equivalent Matrix Equation.

x + 8y = -37

4x + 8y = -52

4 0

1 year ago

A researcher wants to estimate the true proportion of people who would buy items they know are slightly defective from thrift sh

belka [17]

Answer: 0.283

Step-by-step explanation:

Formula to find the lower limit of the confidence interval for population proportion is given by :-

$\hat{p}- z^*\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

, where $\hat{p}$ = sample proportion.

z* = Critical value

n= Sample size.

Let p be the true proportion of people who would purchase a defective item.

Given : Sample size = 993

Number of individuals would buy a slightly defective item if it cost less than a dollar = 305

Then, sample proportion of people who would purchase a defective item:

$\hat{p}=\dfrac{305}{993}\approx0.307$

Critical value for 90% confidence interval = z*=1.645 (By z-table)

The lower bound of a 90% confidence interval for the true proportion of people who would purchase a defective item will become

$0.307-(1.645)\sqrt{\dfrac{0.307(1-0.307)}{993}}$

$0.307- (1.645)\sqrt{0.000214250755287}$

$0.307- 0.024078369963=0.282921630037\approx0.283$ [rounded to the nearest three decimal places.]

Hence, the lower bound of a 90% confidence interval for the true proportion of people who would purchase a defective item.= 0.283

8 0

3 years ago