Question

2x^2-28=10x Factor then solve?

Answer 1

2x^2-28=10x

x^2-14=5x

x^2-5x-14=0

(x-7)(x+2)=0

x = 7, -2

Answer 2

Answer: Yeah. Factor by grouping because it’s the easiest.

Step-by-step explanation:

2x^2-28=10x

-10x -10x

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2x^2-10x-28 = 0

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(2x^2+4x)(-14x-28)=0

You subtract the 10x from both sides and get 2x^2-10x-28 = 0. Then you group. Two parentheses have to be made. Put the 2x^2 in one and the -38 in the other. Multiply the 2 (leading coefficient) by the -28 and get -56. You need two numbers that multiply to -56 but add to -10. Those numbers are -14 and 4. So it’s (2x^2+4x)(-14x-28)=0. Then you just solve. Sorry bout the wordy-ness.