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3 years ago

A line has unit slope and passes through point origin (0,0) . What is the equation of the line?

1 answer:

7 0

Y=x
You exclude the y-intercept because it has a value of zero. Therefore you would right an equation that passes through point (0,0) as y=x or y=x+0.

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Helpppp me plz any help would work :)

mixer [17]

Answer:

2d+3 dollars

Step-by-step explanation:

the second one 2d+3

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3 years ago

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if there were 243 students and 2 students that were out of state were chosen every time 7 of the students that were in state wer

katen-ka-za [31]

The ratio 2:7. Add 7 and 2 together to get 9. Then divide 243 by 9 which is 27. 27x2 is 54 so. There was 54 students out of state. And 189 that were in state

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3 years ago

Would you rather have a kilogram of quarters or a kilogram of dimes? Why?

True [87]

Answer:kilogram of quarters

Step-by-step explanation:

because quarters equal 25 cents each and it’s a kilogram

8 0

3 years ago

What is the slope of the line that contains the points in the table?

Debora [2.8K]

Answer:

Step-by-step explanation:

The boxes with whole numbers in them written as coordinates:

(-4, -11)

(8, -8)

we know gradient is rise over run, or (y2 - y1) / (x2 - x1)

gradient = (-8 - -11) / (8 - -4)

gradient = 3 / 12

gradient = ¼

4 0

2 years ago

Read 2 more answers

Two cars enter the Delaware turnpike at shoreline drive at 8 am, each heading for ocean city. One cars average speed is 10 mph f

lana [24]

Average speed of slower car = 60 mph

Average speed of faster car = 70 mph

Solution:

Given that Two cars enter the Delaware turnpike at shoreline drive at 8 am, each heading for ocean city

Given that One cars average speed is 10 mph faster than the other

Let "x" be the average speed of slower car

Then x + 10 is the average speed of faster car

The faster car arrives at ocean city at 11 am, a half hour before the slower car

Time taken by faster car:

The faster car arrives at ocean city at 11 am but given that they start at 8 a.m

So time taken by faster car = 11 am - 8am = 3 hours

Time taken by slower car:

The faster car arrives at ocean city at 11 am, a half hour before the slower car

So slower car takes half an hour more than faster car

Time taken by slower car = 3 hour + half an hour = $3\frac{1}{2} \text{ hour}$

Now the distance between Delaware turnpike at shoreline drive and ocean city will be same for both cars

Let us equate the distance and find value of "x"

The distance is given by formula:

$distance = speed \times time$

Distance covered by faster car:

$distance = (x + 10) \times 3 = 3x + 30$

Distance covered by slower car:

$distance = x \times 3\frac{1}{2} = x \times \frac{7}{2} = 3.5x$

Equating both the distance,

3x + 30 = 3.5x

3x - 3.5x = -30

-0.5x = -30

x = 60

Thus average speed of slower car = 60 mph

Average speed of faster car = x + 10 = 60 + 10 = 70 mph

8 0

3 years ago