ANSWER
Frequency=2
Midline =3
Amplitude =5
Period =π
EXPLANATION
We have:
The given function is of the form;
where
a=|5| =5 is the amplitude
and b=2 is the frequency.
and 2π/b=2π/2=π
The range of the given function is
8≤y≤-2
The midline is
Use a Mohr circle to find the maximum shear stress relative to the axial stress.
Here we assume the axial stress is sigma, the transverse axial stress is zero.
So we have a Mohr circle with (0,0) and (0,sigma) as a diameter.
The centre of the circle is therefore (0,sigma/2), and the radius is sigma/2.
From the circle, we determine that the maximum stress is the maximum y-axis values, namely +/- sigma/2, at locations (sigma/2, sigma/2), and (sigma/2, -sigma/2).
Given that the maximum shear stress is 60 MPa, we have
sigma/2=60 MPa, or sigma=120 MPa.
(note: 1 MPa = 1N/mm^2)
Therefore
100 kN/(pi*d^2/4)=100,000 N/(pi*d^2/4)=120 MPa where d is in mm.
Solve for d
d=sqrt(100,000*4/(120*pi))
=32.5735 mm
Angles 4,2,6,and 8 are all 106 degrees. To find the other number, subtract 106 from 180 and that is the rest of the numbers. All you have to do is write the measure (m) of the angle listed.
180-106=74 So,
1) 74 degrees
2)106 degrees
3)74 degrees
4) 106 degrees
5)74 degrees
6)74 degrees
Answer:
27
Step-by-step explanation:
Let x represent the number of $0.15 stamps Ivan bought. Then the value of his stamps is ...
0.15x +0.40(35-x) = 7.25
-0.25x +14.00 = 7.25 . . . . . eliminate parentheses, collect terms
-0.25x = -6.75 . . . . . . . . . . . subtract 14.00
x = 27 . . . . . . . . . . . . . . . . . . divide by -0.25
Ivan bought 27 $0.15 stamps.
Answer:
4 cm
Step-by-step explanation:
x^2 = bh
b = 2x
h = x-2
x^2 = (2x)(x-2)
4^2=[2(4)][4-2]
16 = 16
