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3 years ago

Can you please help me on this. Thank you

Mathematics

1 answer:

kap26 [50]3 years ago

5 0

Answer:

9 yds

Step-by-step explanation:

tbh if you go with adding angles it cnt be greater then 18 beacuse the longest segment is the hypotenuse but with its corresponding angle deing 30 degrees then we know it is the shortest in length

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Suppose that a large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved. Another br

aliya0001 [1]

Answer:

$A=1500-1450e^{-\dfrac{t}{250}}$

Step-by-step explanation:

The large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved.

Volume = 500 gallons

Initial Amount of Salt, A(0)=50 pounds

Brine solution with concentration of 2 lb/gal is pumped into the tank at a rate of 3 gal/min

$R_{in}$ =(concentration of salt in inflow)(input rate of brine)

$=(2\frac{lbs}{gal})( 3\frac{gal}{min})\\R_{in}=6\frac{lbs}{min}$

When the solution is well stirred, it is then pumped out at a slower rate of 2 gal/min.

Concentration c(t) of the salt in the tank at time t

Concentration, $C(t)=\dfrac{Amount}{Volume}=\dfrac{A(t)}{500}$

$R_{out}$ =(concentration of salt in outflow)(output rate of brine)

$=(\frac{A(t)}{500})( 2\frac{gal}{min})\\R_{out}=\dfrac{A}{250}$

Now, the rate of change of the amount of salt in the tank

$\dfrac{dA}{dt}=R_{in}-R_{out}$

$\dfrac{dA}{dt}=6-\dfrac{A}{250}$

We solve the resulting differential equation by separation of variables.

$\dfrac{dA}{dt}+\dfrac{A}{250}=6\\$The integrating factor: e^{\int \frac{1}{250}dt} =e^{\frac{t}{250}}\\$Multiplying by the integrating factor all through\\\dfrac{dA}{dt}e^{\frac{t}{250}}+\dfrac{A}{250}e^{\frac{t}{250}}=6e^{\frac{t}{250}}\\(Ae^{\frac{t}{250}})'=6e^{\frac{t}{250}}$

Taking the integral of both sides

$\int(Ae^{\frac{t}{250}})'=\int 6e^{\frac{t}{250}} dt\\Ae^{\frac{t}{250}}=6*250e^{\frac{t}{250}}+C, $(C a constant of integration)\\Ae^{\frac{t}{250}}=1500e^{\frac{t}{250}}+C\\$Divide all through by e^{\frac{t}{250}}\\A(t)=1500+Ce^{-\frac{t}{250}}$

Recall that when t=0, A(t)=50 (our initial condition)

$50=1500+Ce^{-\frac{0}{250}}50=1500+Ce^{0}\\C=-1450\\$Therefore the amount of salt in the tank at any time t is:\\A=1500-1450e^{-\dfrac{t}{250}}$

4 0

4 years ago

Plzz help me I am timed

Viefleur [7K]

Answer:

the answer is b which is 5 ten dollar bill

4 0

4 years ago

Read 2 more answers

FIRST PERSON WHO ANSWERES CORRECTLY GETS A BRAINLIEST AND THIS IS WORTH 12 POINTS

KatRina [158]

Here is your answer

Area of 2 triangular part
=2× (1/2 × 3 × 4)

=12 sq. units

Area of three rectangular parts= (l×b)

= 11×5 + 11×4 + 11×3

= 55+44+33

= 132 sq. units

Hence,

surface area of prism= 12+132

= 144 sq. units

HOPE IT IS USEFUL

3 0

3 years ago

Help me answer this plzzz

Dvinal [7]

Answer:

true

Step-by-step explanation:

8 0

3 years ago

Tyler painted 9/2 square yards of wall area with 3 gallons of paint. How many gallons of paint does it take to paint each square

777dan777 [17]

Answer:

it takes 2/3 gallons to paint each square yard of wall.

You know that Tyler painted 9/2 square yards area with 3 gallons of paint and want to know many gallons of paint does it take to paint each square yard of wall.

Then 9/2 square yards - 3 gallons

1 square yards - x gallons,

mathematically this is proportion: (in the picture)

7 0

3 years ago