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2 years ago

7

Help me answer this plzzz

1 answer:

Dvinal [7]2 years ago

8 0

Answer:

true

Step-by-step explanation:

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Solve the following differential equation: y" + y' = 8x^2

PtichkaEL [24]

Answer:

$y=y_p+y_h = \frac{8}{3}x^3-8x^2+16x+ C_1 + C_2e^{-x}$

Step-by-step explanation:

Let's find a particular solution. We need a function of the form $y= ax^3+bx^2+cx+d$ such that

$y'= 3ax^2+2bx+c$ and

$y''= 6ax+2b$

$y'+y''= 3ax^2+2bx+c+6ax+2b = 3ax^2+x(2b+6a)+(c+2b) = 8x^2$

then, 3a= 8, 2b+6a =0 and c+2b = 0. With the first equation we obtain

a = 8/3 and replacing in the second equation 2b+6(8/3) = 2b + 16 = 0. Then, b = -8. Finally, c = -2(-8) = 16.

So, our particular solution is $y_p= \frac{8}{3}x^3-8x^2+16x$ .

Now, let's find the solution $y_p$ of the homogeneus equation $y''+y'=0$ with the method of constants coefficients. Let $y=e^{\lambda x}$

$y'=\lambda e^{\lambda x}$

$y''=\lambda^2e^{\lambda x}$

then $\lambda e^{\lambda x}+\lambda^2 e^{\lambda x} = 0$

$e^{\lambda x}(\lambda +\lambda^2)= 0$

$(\lambda +\lambda^2)= 0$

$\lambda (1+\lambda)= 0$

$\lambda =0$ and $\lambda)= -1$ .

So, $y_h = C_1 + C_2e^{-x}$ and the solution is

$y=y_p+y_h =\frac{8}{3}x^3-8x^2+16x+ C_1 + C_2e^{-x}$ .

5 0

2 years ago

Helppppppppppppppppppppppp

tresset_1 [31]

Since it’s not x3 it must be +8 so if i were you i’d pick B

7 0

2 years ago

A map of Brasilia has a scale of 1 inch to 5 miles. If the city is 2 7/16 inches across on the map, what is the distance across

Vinvika [58]

The answer is c because that is what the website said with the exact same question , I hope you don't need to show your work but the correct answer is c

7 0

3 years ago

Read 2 more answers

Help me please!..

AlexFokin [52]

Answer:

44 times

Step-by-step explanation:

There is a 50% (2/4) chance that this could occur, as given in the question.

88*.5 = 44.

8 0

2 years ago

Find the inverse for each relation {(-5,1),(-5,-1)(-5,8)}

kobusy [5.1K]

Answer:

(-5,7) (-5,8) (-5,3)

Step-by-step explanation:

Dont know if this will help but here you go

3 0

2 years ago