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3 years ago

How can transformations be used to solve real world problems?

1 answer:

6 0

Transformations, im assuming, you mean the ones with graphs on which you move things (ie, x+3; y-10)

imagine setting the table, and you need to add an extra chair for a guest, what do you do?

you transform the x and y of the stuff on one side of the table over, to make room for a new chair and set of tableware. though i dont know if thats a good example

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Answer ASAP will mark brainiest

USPshnik [31]

Answer:

64 Maybe

Step-by-step explanation:

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3 years ago

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An item is regularly priced at $75. It is now priced at a discount of 35% off the regular price. Find the price now.

Reptile [31]

Answer:

48.75

Step-by-step explanation:

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3 years ago

Six posts are evenly spaced along a circular wall encasing a fountain. Anna stands at point A, where she cannot see beyond the o

inn [45]

There are 6 points on a circle.

We have a sum of angles in a circle that is equal to 360°.

Anna can only see 2 points which is a third of a points there are.

That means her spectrum is 360°/3 which is 120°.

The answer is B. 120°.

Hope this helps.

Brainliest would be amazing.

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3 years ago

Line segment AB has endpoints A(6,1) and B(3,8). Find the coordinates of the point that divides the line segment directed from A

VLD [36.1K]

Hope this helps. Then add -3/5 to the x value of 6 and add 7/5 to the y value of 1. Do the same to the next coordinates and you'll get your answer.

5 0

4 years ago

Read 2 more answers

The U.S. Energy Information Administration (US EIA) reported that the average price for a gallon of regular gasoline is . The US

alexandr1967 [171]

Answer:

The answer is "23, 62, and 139"

Step-by-step explanation:

In point a:

$\to \sigma = \$0.24\\\\ \to E = \$0.10\\\\ 95\% \text{confidence level of the z}: \\\\\to \alpha = 1 - 95\% = 1 - 0.95 = 0.05\\\\\to \frac{\alpha}{2} = \frac{0.05}{2} = 0.025\\\\\to Z_{\frac{\alpha}{2}} = Z_{0.025} = 1.96\\\\$

Calculating the sample size:

$\to n = (\frac{(Z_{\frac{\alpha}{2}} \times \sigma)}{E})^2$

$= (\frac{(1.96 \times 0.24 )}{0.10})^2\\\\= 22.13 \approx 23$

In point b:

$\to \sigma = \$0.24\\\\\to E = \$0.06\\\\\to Z_{\frac{\alpha}{2}} = Z_{0.025} = 1.96\\\\\to n = (\frac{(Z_{\frac{\alpha}{2}} \times \sigma )}{E})^2\\\\$

$= (\frac{(1.96 \times 0.24 )}{0.06})^2\\\\= 61.47 \approx 62$

In point c:

$\to \sigma = \$0.24\\\\\to E =\$0.04\\\\\to Z_{\frac{\alpha}{2}} = Z_{0.025} = 1.96\\\\\to n = (\frac{(Z_{\frac{\alpha}{2}} \times \sigma )}{E})^2\\\\$

$= (\frac{(1.96\times 0.24 )}{0.04})^2 \\\\=138.30 \approx 139$

4 0

3 years ago