Question

An isosceles triangle has a perimeter of 36 inches. Its base is 2

Answer 1

The lengths of the sides of the triangle are 8, 8, 20

Explanation:

Given that the perimeter of an isosceles triangle is 36 inches.

The base of the triangle is $2\frac{1}{2}$ times longer than each of its legs.

We need to determine the lengths of the sides of the triangle.

Lengths of the sides:

Let x denote the lengths of the sides of the triangle.

The base of the triangle is given by

$2\frac{1}{2}x=\frac{5}{2}x=2.5x$

Perimeter of the isosceles triangle = Sum of the three sides of the triangle.

Thus, we have,

$36=x+x+2.5x$

$36=4.5x$

$8=x$

Thus, the length of the sides of the isosceles triangle is 8 inches.

Base of the triangle = $2.5(8)=20 \ inches$

Hence, the three sides of the isosceles triangle are 8, 8, 20