What is the domain of the function y= (square root) x+4

Mathematics

1 answer:

garri49 [273]3 years ago

6 0

Answer:

0 ≤ x ≤ ∞

Step-by-step explanation:

Square roots <em>always</em> need to be either equal to or greater than zero because it should be positive inside (unless we're working with imaginary numbers).

So the domain would be that x ≥ 0 (or the third choice ⇒ 0 ≤ x ≤ ∞).

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Sarina throws a ball up into the air, and it falls on the ground nearby. The ball's height, in feet, is modeled by the function

tangare [24]

Answer:

Step-by-step explanation:

We have a function of f(x) here. When Sarina throws the ball, it has been 0 seconds since she threw it.

Since x represents the amount of seconds, we can find the height of the ball (f(x)) by substituting x in as 0.

$-0^2 - 0 + 3$

0 squared is 0, 0 minus zero is 0, and 0+3 = 3, so

$f(x) = 3$

Meaning that when Sarina threw the ball, it's height was 3 feet.

Hope this helped!

7 0

3 years ago

Which is equivalent to this expression?<br> 2/150 + 3/75

Lesechka [4]

Answer:

Step-by-step explanation:

$\frac{2}{150}$ First reduce this to lowest term

$\frac{2}{150}=\frac{1}{75}\\\\\frac{2}{150}+\frac{3}{75}=\frac{1}{75}+\frac{3}{75}\\\\=\frac{1+3}{75}=\frac{4}{75}\\$

7 0

4 years ago

What is the area of a parallelogram if its length is x+4 and its height is x+3

lord [1]

Area of a parallelogram is:

$\sf A=bh$

Where 'b' is the base and 'h' is the height. Plug in what we know:

$\sf A=(x+4)(x+3)$

Distribute(multiply everything in the first parenthesis to everything in the second parenthesis):

$\sf x\times x=x^2$
$\sf x\times 3=3x$
$\sf 4\times x=4x$
$\sf 4\times 3=12$

So we have:

$\sf A=x^2+3x+4x+12$

Combine like terms(3x + 4x = 7x):

$\sf A=\boxed{\sf x^2+7x+12}$