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kirza4 [7]
3 years ago
9

Please solve...Thanks

Mathematics
1 answer:
liberstina [14]3 years ago
3 0
Micheal has 40ft of fencing for the rectangular dog run. So the perimeter of the dog run is 40ft.

Perimeter=40ft

The perimeter of a rectangle is:

P=2l+2w

Since we know the length is 5 and the perimeter is 40, we can solve for the width.

P=2l+2w
40=2*(5)+2w
40=10+2w
subtract 10 from both sides
30=2w
divide both sides by 2
15=w

The width of the fence is 15feet.

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Let f(x) = 4x – 1, h(x) = -x-1.<br><br> Find (f o h)(6)<br><br> (foh)(6) =
Ludmilka [50]

Answer:

(foh)(6) = -29

Step-by-step explanation:

(f o h)(6) is f(h(x)) when x = 6.

We have that:

f(x) = 4x - 1

h(x) = -x-1

f(h(x)) = 4(-x-1) - 1 = -4x - 4 - 1 = -4x - 5

(foh)(6) = -4(6) - 5 = -29

(foh)(6) = -29

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3 years ago
The area of a rectangle is 120cm and its length is 12cm .Calculate the width of the rectangle
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3 0
3 years ago
Please help me with this
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Answer:

The length= 16cm

The width= 6cm

The two long sides are 8cm both so 8 + 8 = 16

And the two short sides are 3cm both so 3 + 3 = 6

So your length should be 16cm and your width 6cm

I HOPE THIS HELPS! ∧   ∧

                              ⊂∵→ω←∵⊃

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