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grigory [225]
2 years ago
14

The average number of pounds of red meat a person consumes each year is 196 with a standard deviation of 22 pounds (source: amer

ican dietetic association). if a sample of 50 individuals is randomly selected, find the probability that the mean of the sample will be less than 200 pounds.
Mathematics
1 answer:
disa [49]2 years ago
7 0
Given:
Mean, μ = 196
Std. dev., σ = 22
A sample size of 50 (> 30) is large enough to provide meaningful data.

The random variable is x = 200.
The z-score is
z = (x - μ)/σ = (200 - 196)/22 = 0.1818

From normal distribution tables, obtain
Prob(X < 200) = 0.572 = 57.2%

Answer: 57.2%
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Answer:

45% of the people are in the water

Step-by-step explanation:

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6 0
3 years ago
Distributive Property Using GCF<br><br> 25 + 30
postnew [5]

Hey there! I'm happy to help!

Let's look at the factors of each of these numbers.

25

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The greatest common factor between these is 5. Therefore, we divide 25+30 by 5 and put the 5 on the outside.

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This has the same value but it is just written differently.

Have a wonderful day! :D

3 0
3 years ago
Answer with explanation plz
Nostrana [21]
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7 0
3 years ago
The cost of parking a motor home in a state park includes a one time fee of $180, plus a daily rate of $55 per day. Anthony prep
HACTEHA [7]

Answer:

Anthony paid for 7 days of parking.

Step-by-step explanation:

From the information given, the cost of parking a motor home in a state park would be equal to the one time fee plus the result of multiplying the daily rate for the number of days:

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Now, you can replace c with 565 that is the amount Anthony prepaid and you can solve for x to be able to find the number of days he paid for:

565=180+55x

565-180=55x

385=55x

x=385/55

x=7

According to this, Anthony paid for 7 days of parking.

7 0
2 years ago
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Answer:

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3 years ago
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