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2 years ago

Which one is equivalentform of the compound inequality -33 > -3x - 6 >_ -6?

Mathematics

1 answer:

elena55 [62]2 years ago

3 0

Answer:

Step-by-step explanation:

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Kimberly drives at a rate of 50 miles per hour on her trip across the country. If it takes Kimberly 200 gallons of gasoline to d

ipn [44]

Answer:

Step-by-step explanation:

50 mi/hr × (1 hr / 60 min) × (200 gal / 500 mi) = ⅓ gal/min

(⅓ gal/min) × (t min) = x gal

t = 3x

3 0

3 years ago

James asked 60 pupils which drink they liked best from cola, milk and water.

Olin [163]

Answer:

Step-by-step explanation:

There are 60 pupils in the survey

32 are boys, so we assume 28 are girls

12 of the boys said cola was their favourite

4 boys liked water best.

That is a total of 16 boys who prefer either cola or water out of 32 total boys

There are 16 boys leftover who must have milk as there favourite

9 girls liked water best

21 pupils altogether said milk was there favourite. We know there are 16 boys who said milk was there favourite, meaning 5 of these pupils must be girls.

That means 9 girls have water as their favourite and 5 have milk as their favourite, a total of 14

We know there are 28 girls total. That means 14 of them must have listed cola as their favourite drink.

There are 14 girls and 12 boys who said cola was their favourite, a total of 26 pupils

6 0

3 years ago

Help please mathematics due today

3241004551 [841]

Answer:

Step-by-step explanation:were the work at

7 0

3 years ago

Can I get help with finding the Fourier cosine series of F(x) = x - x^2

trapecia [35]

Assuming you want the cosine series expansion over an arbitrary symmetric interval $[-L,L]$ , $L\neq0$ , the cosine series is given by

$f_C(x)=\dfrac{a_0}2+\displaystyle\sum_{n\ge1}a_n\cos nx$

You have

$a_0=\displaystyle\frac1L\int_{-L}^Lf(x)\,\mathrm dx$
$a_0=\dfrac1L\left(\dfrac{x^2}2-\dfrac{x^3}3\right)\bigg|_{x=-L}^{x=L}$
$a_0=\dfrac1L\left(\left(\dfrac{L^2}2-\dfrac{L^3}3\right)-\left(\dfrac{(-L)^2}2-\dfrac{(-L)^3}3\right)\right)$
$a_0=-\dfrac{2L^2}3$

$a_n=\displaystyle\frac1L\int_{-L}^Lf(x)\cos nx\,\mathrm dx$

Two successive rounds of integration by parts (I leave the details to you) gives an antiderivative of

$\displaystyle\int(x-x^2)\cos nx\,\mathrm dx=\frac{(1-2x)\cos nx}{n^2}-\dfrac{(2+n^2x-n^2x^2)\sin nx}{n^3}$

and so

$a_n=-\dfrac{4L\cos nL}{n^2}+\dfrac{(4-2n^2L^2)\sin nL}{n^3}$

So the cosine series for $f(x)$ periodic over an interval $[-L,L]$ is

$f_C(x)=-\dfrac{L^2}3+\displaystyle\sum_{n\ge1}\left(-\dfrac{4L\cos nL}{n^2L}+\dfrac{(4-2n^2L^2)\sin nL}{n^3L}\right)\cos nx$

4 0

3 years ago

Plsss help (brainliest if right!)

Blizzard [7]

Answer: Simple, it got Translated according to the rule (x, y) → (x + 2, y + 8) and reflected across the y-axis

Step-by-step explanation:

4 0

2 years ago