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matrenka [14]
3 years ago
7

Which one is equivalentform of the compound inequality -33 > -3x - 6 >_ -6?

Mathematics
1 answer:
elena55 [62]3 years ago
3 0

Answer:

Step-by-step explanation:

Hi

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What function is graphed below?
tester [92]
The answer for the exercise shown above is the first option, which is:
<span> f(x)=log(x-3) 
 The explanation is shown below:
 If you substitute the x in the function for values, you will obtain the graph attached above. As you can see on the mentioned graph, when the variable x has the value 4, the value y is 0. Therefore, you have:
 </span> f(x)=log(x-3) 
  f(x)=log(4-3) 
  f(x)=log(1)
  f(x)=0<span>
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3 0
3 years ago
Read 2 more answers
4. If A = (-4, -5) and B = (-1, -10), what is the length of segment AB? Round your answer to the nearest hundredth.
HACTEHA [7]

Answer:

5.83095 or √34

Step-by-step explanation:

Find the difference between coordinates:

(x2-x1) = (-1 - -4) = 3

(y2-y1) = (-10 - -5) = -5

Square the results and sum them up:

(3)2 + (-5)2 = 9 + 25 = 34

Now Find the square root and that's your result:

Exact solution: √34 = √34

Approximate solution: 5.831

7 0
3 years ago
5) A submarine is cruising at -40 meters (40 meters below the surface). It
Verdich [7]

Answer:

-25

Step-by-step explanation:

You begin with -40, then decrease by 20 so your new value is -60, then increase by 35 so your final value is -25m... hope this helps (:

5 0
4 years ago
What are good ideas for a jingle thing?
Masja [62]

Answer:

Please evaluate



6 0
3 years ago
OC and OR are similar. Find the length of QP.
Elena L [17]

Given:

Circle C and circle R are similar.

The length of arc AB is s = \frac{22 \pi}{9}

The radius of circle C (AC) = 4 unit

The radius of circle R (QR) =6 unit

To find the length of arc QP.

Formula

The relation between s,  r and \theta is

arclength = 2\pi r \frac{\theta}{360}

where,

s be the length of the arc

r be the radius

\theta be the angle.

Now,

For circle C

Taking r = 4

According to the problem,

2 \pi r \frac{\theta}{360} = \frac{22 \pi}{9}

or, 2r \frac{\theta}{360} = \frac{22}{9} [ eliminating \theta from both side]

or, \theta = \frac{(22)(360)}{(9)(2)(4)}

or, \theta = 110^\circ

Again,

For circle R

Taking, r = 6 and \theta = 110^\circ we get,

The length of arc QP is

arc length = 2\pi (6)(\frac{110}{360} )

or, arclength = \frac{11 \pi}{3}

Hence,

The length of QP is \frac{11 \pi}{3}. Option C.

5 0
3 years ago
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