Answer:
Step-by-step explanation:
Hello,
x²-5x-36=x²-9x+4x-36
=x(x-9)+4(x-9)
=(x-9)(x+4)
Answer:
k = 4
Step-by-step explanation:
Plug in the values of 2 for x and 0 for y, and solve for k.
2x + 3y = k
2(2) + 3(0) = k
4 = k
k = 4
Answer:
If you are <u>traversing squares</u> then 7 different paths can be taken
If you are <u>traversing edges </u> then 36 different paths can be taken
Step-by-step explanation:
I have attached a picture that would describe the grid which is 7 units long.
The solution to the general problem is if you have to take X right steps, and Y down steps then the number of routes is simply the ways of choosing where to take the down (or right) steps. Such that:
![\left (\ {X+Y} \atop {X}} \right.\left)=\left (\ {X+Y} \atop {Y}} \right.\left)](https://tex.z-dn.net/?f=%5Cleft%20%28%5C%20%7BX%2BY%7D%20%5Catop%20%7BX%7D%7D%20%5Cright.%5Cleft%29%3D%5Cleft%20%28%5C%20%7BX%2BY%7D%20%5Catop%20%7BY%7D%7D%20%5Cright.%5Cleft%29)
Basically its the combination of terms.
In this problem,
If you are <u>traversing squares</u> then there are 6 right steps and 1 down step,
7 C 1 = 7 C 6= 7
If you are <u>traversing edges </u> then there are 7 right steps and 2 down steps:
9 C 2 = 9 C 7= 36
Let airspeed of the plane be x mph and wind speed = y mph. Then we have the following system of equations
x - y = 1160 / 4.833 = 240.0166
and
x + y = 1160 / 4 = 290
adding the 2 equations:-
2x = 530.0166
x = 265 mph = airspeed of the plane
y = 290 - 265 = 25 mph = speed of the wind