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Oksana_A [137]
3 years ago
12

Sigma notation from sum. pls help?? sorry for the calc spam :P

Mathematics
1 answer:
givi [52]3 years ago
7 0
To the risk of sounding redundant,

\bf \begin{array}{ccccccccc}
k=2&&k=3&&k=4&&k=5&&k=6\\\\
\frac{\underline{2}+2}{2(\underline{2})}&&\frac{\underline{3}+2}{2(\underline{3})}&&\frac{\underline{4}+2}{2(\underline{4})}&&\frac{\underline{5}+2}{2(\underline{5})}&&\frac{\underline{6}+2}{2(\underline{6})}\\\\
1&+&\cfrac{5}{6}&+&\cfrac{6}{8}&+&\cfrac{7}{10}&+&\cfrac{8}{12}
\end{array}

and surely you'd know what that is.
You might be interested in
Solve - pv + 40 &lt; 65 for v<br> solve 7w - 3r = 15 for r
Katarina [22]

Answer:

v > -25/p

r = -5 +7/3 w

Step-by-step explanation:

- pv + 40 < 65

Subtract 40 from each side

- pv + 40-40 < 65-40

-pv < 25

Divide each side by -p  (remember to flip the inequality since we are dividing by a negative)

-pv/-p > 25/-p

v > -25/p


7w - 3r = 15

Subtract 7w from each side

7w-7w - 3r = 15-7w

-3r = 15-7w

Divide by -3

-3r/-3 = (15-7w)/-3

r = -5 +7/3 w

8 0
3 years ago
An Equilateral Triangle has sides that all measure 10 inches. What is
densk [106]

Answer:

easy peasy lemon squeasy

Step-by-step explanation:

1. base of triangle: it is an equilateral triangle, so any side of the triangle you take is the base, (usually the largest side of the triangle is the base)

so that would be => 10 inches,

2. a property of an equilateral triangle is that , the median of the triangle coincides with the height of the triangle,

therefore, the height bisects the base and makes a right triangle with another side, therefore by using the Pythagoras theorem, we find it to be 8.66(approx)

now,

area of the triangle would be (putting the values we just found in the formula given)

=> [(10)(8.66)]/ 2

=>43.3 square inches

4 0
3 years ago
Plsss help ill give brainiest
Elena L [17]

To solve this problem, we have to use the area of both gauze or the dimensions on each gauze and compare them. we can see that the sheets are not similar as they have different areas.

<h3>Area of Rectangle</h3>

The area of a rectangle is given as the product between the length and it's width.

Data;

  • Length = 9in
  • Area = 45in^2
  • width = ?
  • length 2 = 4in
  • width 2 = 3in

area = length * width

In the first gauze, the area is given as 45in^2 and we have value of the length. To find the width of the first gauze can be calculated as

A = length * width\\width = \frac{area}{length} \\width = \frac{45}{9} \\width = 5in

We can see that the width are not equal so is their length.

But if we would truly compare them, the accurate way to do that is by their area

The area of the second gauze is given by

a = 3 * 4 = 12in^2

From the above calculations, we can see that the sheets are not similar as they have different areas.

Learn more on area of a rectangle here;

brainly.com/question/25292087

3 0
2 years ago
Please help me <br> Show your work <br> 10 points
Svet_ta [14]
<h2>Answer</h2>

After the dilation \frac{5}{3} around the center of dilation (2, -2), our triangle will have coordinates:

R'=(2,3)

S'=(2,-2)

T'=(-3,-2)

<h2>Explanation</h2>

First, we are going to translate the center of dilation to the origin. Since the center of dilation is (2, -2) we need to move two units to the left (-2) and two units up (2) to get to the origin. Therefore, our first partial rule will be:

(x,y)→(x-2, y+2)

Next, we are going to perform our dilation, so we are going to multiply our resulting point by the dilation factor \frac{5}{3}. Therefore our second partial rule will be:

(x,y)→\frac{5}{3} (x-2,y+2)

(x,y)→(\frac{5}{3} x-\frac{10}{3} ,\frac{5}{3} y+\frac{10}{3} )

Now, the only thing left to create our actual rule is going back from the origin to the original center of dilation, so we need to move two units to the right (2) and two units down (-2)

(x,y)→(\frac{5}{3} x-\frac{10}{3}+2,\frac{5}{3} y+\frac{10}{3}-2)

(x,y)→(\frac{5}{3} x-\frac{4}{3} ,\frac{5}{3}y+ \frac{4}{3})

Now that we have our rule, we just need to apply it to each point of our triangle to perform the required dilation:

R=(2,1)

R'=(\frac{5}{3} x-\frac{4}{3} ,\frac{5}{3}y+ \frac{4}{3})

R'=(\frac{5}{3} (2)-\frac{4}{3} ,\frac{5}{3}(1)+ \frac{4}{3})

R'=(\frac{10}{3} -\frac{4}{3} ,\frac{5}{3}+ \frac{4}{3})

R'=(2,3)

S=(2,-2)

S'=(\frac{5}{3} (2)-\frac{4}{3} ,\frac{5}{3}(-2)+ \frac{4}{3})

S'=(\frac{10}{3} -\frac{4}{3} ,-\frac{10}{3}+ \frac{4}{3})

S'=(2,-2)

T=(-1,-2)

T'=(\frac{5}{3} (-1)-\frac{4}{3} ,\frac{5}{3}(-2)+ \frac{4}{3})

T'=(-\frac{5}{3} -\frac{4}{3} ,-\frac{10}{3}+ \frac{4}{3})

T'=(-3,-2)

Now we can finally draw our triangle:

8 0
3 years ago
Help‼️‼️‼️Answer part 3,4,5 and give several equations for each show your work‼️
soldi70 [24.7K]

Answer:

I'd really love to help you but the way you asked made you sound so needy and that just made me not want to answer sorry...

Step-by-step explanation:

5 0
3 years ago
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