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Oksana_A [137]
3 years ago
12

Sigma notation from sum. pls help?? sorry for the calc spam :P

Mathematics
1 answer:
givi [52]3 years ago
7 0
To the risk of sounding redundant,

\bf \begin{array}{ccccccccc}
k=2&&k=3&&k=4&&k=5&&k=6\\\\
\frac{\underline{2}+2}{2(\underline{2})}&&\frac{\underline{3}+2}{2(\underline{3})}&&\frac{\underline{4}+2}{2(\underline{4})}&&\frac{\underline{5}+2}{2(\underline{5})}&&\frac{\underline{6}+2}{2(\underline{6})}\\\\
1&+&\cfrac{5}{6}&+&\cfrac{6}{8}&+&\cfrac{7}{10}&+&\cfrac{8}{12}
\end{array}

and surely you'd know what that is.
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Hey, I need some help in math I put the pic down below
EastWind [94]

For this case we have that by definition, the equation of a line in the slope-intersection form is given by:

y = mx + b

Where:

m: It's the slope

b: It is the cutoff point with the y axis

We find the slope with the given points:

m = \frac {y2-y1} {x2-x1} = \frac {401-450} {14-7} = \frac {-49} {7} = - 7

Thus, the line is given by:

y = -7x + b

We substitute a point to find "b":

450 = -7 (7) + b\\450 = -49 + b\\450 + 49 = b\\b = 499

Finally, the equation is:

y = -7x + 499

Answer:

y = -7x + 499

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