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Artyom0805 [142]
2 years ago
13

Solve the equation 6+2x=20 10 points!!!

Mathematics
1 answer:
bulgar [2K]2 years ago
5 0

Answer:

x=7

Step-by-step explanation:

2x=20-6

2x=14

x=14/2

x=7

You might be interested in
How much will the guitar be worth in 10 years?
Contact [7]

Answer:

$44487

Step-by-step explanation:

If you plug in 10 for t, you are left with the following equation:

V=12000(1.14)^{10}=12000\cdot 3.7072\approx 44487. Hope this helps!

8 0
2 years ago
Read 2 more answers
88511, 16351, ?, 10251 missing number in sequence
Mrac [35]

Step-by-step explanation:

this is really complicated and tricky.

to create the next number, you have to add the first 2 digits of the previous number, then subtract the 3rd from the 2nd digit, multiply the 3rd and the 4th digit, and finally divide the 4th digit by the 5th.

so,

8+8 = 16

8-5 = 3

5×1 = 5

1/1 = 1

giving 16351 as next number.

the missing number we get then

1+6 = 7

6-3 = 3

3×5 = 15

5/1 = 5

giving 73155 as the next (missing) number.

control :

7+3 = 10

3-1 = 2

1×5 = 5

5/5 = 1

gives us 10251 as next number - correct.

but then it will end

1+0 = 1

0-2 = -2 ???? take the absolute value ?

2×5 = 10

5/1 = 5

8 0
1 year ago
An area is approximated to be 14 in 2 using a left-endpoint rectangle approximation method. A right- endpoint approximation of t
USPshnik [31]
The trapezoidal approximation will be the average of the left- and right-endpoint approximations.

Let's consider a simple example of estimating the value of a general definite integral,

\displaystyle\int_a^bf(x)\,\mathrm dx

Split up the interval [a,b] into n equal subintervals,

[x_0,x_1]\cup[x_1,x_2]\cup\cdots\cup[x_{n-2},x_{n-1}]\cup[x_{n-1},x_n]

where a=x_0 and b=x_n. Each subinterval has measure (width) \dfrac{a-b}n.

Now denote the left- and right-endpoint approximations by L and R, respectively. The left-endpoint approximation consists of rectangles whose heights are determined by the left-endpoints of each subinterval. These are \{x_0,x_1,\cdots,x_{n-1}\}. Meanwhile, the right-endpoint approximation involves rectangles with heights determined by the right endpoints, \{x_1,x_2,\cdots,x_n\}.

So, you have

L=\dfrac{b-a}n\left(f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1})\right)
R=\dfrac{b-a}n\left(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n)\right)

Now let T denote the trapezoidal approximation. The area of each trapezoidal subdivision is given by the product of each subinterval's width and the average of the heights given by the endpoints of each subinterval. That is,

T=\dfrac{b-a}n\left(\dfrac{f(x_0)+f(x_1)}2+\dfrac{f(x_1)+f(x_2)}2+\cdots+\dfrac{f(x_{n-2})+f(x_{n-1})}2+\dfrac{f(x_{n-1})+f(x_n)}2\right)

Factoring out \dfrac12 and regrouping the terms, you have

T=\dfrac{b-a}{2n}\left((f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1}))+(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n))\right)

which is equivalent to

T=\dfrac12\left(L+R)

and is the average of L and R.

So the trapezoidal approximation for your problem should be \dfrac{14+21}2=\dfrac{35}2=17.5\text{ in}^2
4 0
2 years ago
UVOISINOULLIV HU
Gala2k [10]
<h3>Total snow fall for three days is 8.75 inches</h3>

<em><u>Solution:</u></em>

Given that,

Snow fell over the past three days

First\ day = 3\frac{2}{4}\ inches = \frac{14}{4}\ inches\\\\Second\ day = 3\frac{2}{4}\ inches = \frac{14}{4}\ inches\\\\Third\ day = 1\frac{3}{4}\ inches = \frac{7}{4}\ inches

<em><u>What was the total snowfall for the three days?</u></em>

Total snowfall = first day + second day + third day

Total\ snowfall = \frac{14}{4} + \frac{14}{4} + \frac{7}{4}\\\\Total\ snowfall = \frac{14 + 14 + 7}{4}\\\\Total\ snowfall = \frac{35}{4} \text{ or } 8.75\ inches

Thus total snow fall for three days is 8.75 inches

5 0
3 years ago
Your averages and values are the following:
ioda

Answer: You need a grade of 78 on the final exam to earn a final grade average of at least 87 in each grading system.

Step-by-step explanation:

(85 + 90 + 95 + x)÷ 4 =87

Simplify:

(270 + x) ÷ 4 = 87

Rearrange:

(x + 270) ÷ 4 = 87

Multiply terms to Reduce:

4((x + 270) ÷ 4) = 4 * 87

Cancel Multiplied terms in Denominator:

x + 270 = 4 * 87

Multiply:

x + 270 = 348

Subtract 270 on both sides of the equation:

x + 270 - 270 = 348 - 270

Simplify:

x = 78

6 0
2 years ago
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