Answer:
12 constant terms and 12 variable terms
Step-by-step explanation:
Answer:
- 2(L +W) ≤ 600
- W ≤ 200
- L ≥ 2W
Step-by-step explanation:
We assume the problem wording means the length is to be at least 2 times <em>as long as</em> the width. (<em>Longer than</em> usually refers to a difference, not a scale factor.)
If we let "W" and "L" represent the width and length, respectively, then we can translate the problem statement to ...
2(L + W) ≤ 600 . . . . . . the perimeter is twice the sum of length and width
W ≤ 200 . . . . . . . . . . . . the width is at most 200 inches
L ≥ 2W . . . . . . . . . . . . . the length is at least twice the width
Answer:
80
Step-by-step explanation:
The median is the middle value of the data arranged in ascending order. If there is no exact middle then the median is the average of the 2 values either side of the middle
Arrange the data in ascending order ( smallest to largest )
32, 77, 78, 82, 85, 87
There is no value exactly in the middle, use the average
median =
=
= 80
Answer:14+8c
Step-by-step explanation:
The parent function was moved left one and down five. It also opened up due to the 1/2