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Elodia [21]
3 years ago
7

Jim has made a dartboard using two concentric circles, one blue and one yellow. The distance from the center to the edge of the

blue circle is 8 inches, while from the center to the edge of the yellow circle it is 11 inches. Jim plans to play a game with his friend Randolph, in which the blue region is Jim's and the yellow region is Randolph's.
Is the game FAIR?
Mathematics
1 answer:
oksian1 [2.3K]3 years ago
8 0

Answer:

No; the blue region is larger.

Step-by-step explanation:

The area of the blue region is 64π = 200.96 square inches, while the area of the yellow region is 121π - 64π = 178.98 square inches.

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I really need help do can someone do it step by step so I can understand plzzzz​
Alekssandra [29.7K]

Answer:

64 × pi m²

Step-by-step explanation:

the formulas needed for the surface area of a cone are :

base area plus the "mantle", the lateral "wall" around it.

the base area is a circle.

so, that formula is Ac = pi×r²

the "wall" formula is Aw = pi×r×s

r = radius

s = slant height = 12

the formula for the surface area of a sphere is

As = 4×pi×r²

we know now, that both surface areas are the same, and also the radius is the same for both objects.

Ac + Aw = As

pi×r² + 12×pi×r = 4×pi×r²

=>

12×pi×r = 3×pi×r²

12×pi = 3×pi×r

12 = 3×r

r = 4 m

now, we only need to use this value of r in our formulas for surface areas, like for the sphere :

4×pi×r² = 4×pi×4² = 4³×pi = 64×pi

3 0
3 years ago
A cylinder shaped can needs to be constructed to hold 400 cubic centimeters of soup. The material for the sides of the can costs
LenKa [72]

Answer:

The dimensions of the can that will minimize the cost are a Radius of 3.17cm and a Height of 12.67cm.

Step-by-step explanation:

Volume of the Cylinder=400 cm³

Volume of a Cylinder=πr²h

Therefore: πr²h=400

h=\frac{400}{\pi r^2}

Total Surface Area of a Cylinder=2πr²+2πrh

Cost of the materials for the Top and Bottom=0.06 cents per square centimeter

Cost of the materials for the sides=0.03 cents per square centimeter

Cost of the Cylinder=0.06(2πr²)+0.03(2πrh)

C=0.12πr²+0.06πrh

Recall: h=\frac{400}{\pi r^2}

Therefore:

C(r)=0.12\pi r^2+0.06 \pi r(\frac{400}{\pi r^2})

C(r)=0.12\pi r^2+\frac{24}{r}

C(r)=\frac{0.12\pi r^3+24}{r}

The minimum cost occurs when the derivative of the Cost =0.

C^{'}(r)=\frac{6\pi r^3-600}{25r^2}

6\pi r^3-600=0

6\pi r^3=600

\pi r^3=100

r^3=\frac{100}{\pi}

r^3=31.83

r=3.17 cm

Recall that:

h=\frac{400}{\pi r^2}

h=\frac{400}{\pi *3.17^2}

h=12.67cm

The dimensions of the can that will minimize the cost are a Radius of 3.17cm and a Height of 12.67cm.

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Answer: Double the tax so that hes not a jerc

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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What do you start with?<br> 6(3+8n)=210
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Always start with what’s in the parentheses:)
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