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3 years ago

Find the solution of this system of equations

Mathematics

1 answer:

Rus_ich [418]3 years ago

3 0

Answer:

x=2, y=12

Step-by-step explanation:

8x - 4y = -32

-3x + 4y = 42

add the two equations together to eliminate y

8x - 4y = -32

-3x + 4y = 42

----------------------------

5x = 10

Divide by 5

5x/5 = 10/5

x=2

Now find y

-3x+4y = 42

-3(2) +4y = 42

-6 +4y = 42

Add 6 to each side

-6+6 +4y = 42+6

4y = 48

Divide by 4

4y/4 =48/4

y=12

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The sum of eight times a number and fifteen is seven.Find the number. How do I work this out like these?

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4 years ago

Ryan and Sarah collect baseball cards. Ryan has 150 baseball cards and collects 10 cards per week. Sarah has 233 baseball cards

ICE Princess25 [194]

Answer:

About 17 weeks

Step-by-step explanation:

Given

Ryan:

$Initial = 150$

$Additional = 10$ (weekly)

Sarah:

$Initial = 233$

$Additional = 5$ (weekly)

Required

Determine the number of weeks they have the same cards

Represent the number of weeks with w:

For Both individuals, number of card at any given week is:

$Initial + Additional * w$

So,

For Ryan, the expression is:

$150 + 10 * w$

$150 + 10w$

For Sarah, the expression is:

$233 + 5 * w$

$233 + 5 w$

To determine the number of weeks, we have to equate both equations:

$150 + 10w= 233 + 5 w$

Collect Like Terms

$10w - 5w = 233 - 150$

$5w = 83$

Solve for w

$w = 83/5$

$w = 16.6$

16.6 implies about 17 weeks, because 16.6 approximates to 17

Conclusively, Ryan and Sarah will have the same number of balls in about 17 weeks

5 0

3 years ago

It's a quartile question.

Mkey [24]

Answer:

D. 8

Step-by-step explanation:

the upper quartile = 8

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3 years ago

The total charge that has entered a circuit element is q(t) = 6 (1 - e-7t) when t ≥ 0 and q(t) = 0 when t < 0. The current in

Bess [88]

Answer:

$A=42, B=-7$

Step-by-step explanation:

The current function of time is defined as follows:

$I(t)=\frac{dq(t)}{dt}$

where $q(t)$ is the charge function.

For the given charge function of time $q(t)=6\left( 1-e^{-7t}\right)$ we have the following current function:

$I(t)=\frac{d}{dt} \left(6\left( 1-e^{-7t}\right)\right)=42e^{-7t}$

In the problem it is proposed that $I(t)=Be^{-At}$ .

Examining the expression of $I(t)$ we obtained by deriving $q(t)$ with the expression proposed by the problem and comparing term by term:

$I(t)=Be^{-At}=42e^{-7t}$

We conclude that $A=-7$ and $B=42$ .

4 0

3 years ago