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Brilliant_brown [7]
3 years ago
15

Which rate is equvalent to 55 miles per hour

Mathematics
1 answer:
GuDViN [60]3 years ago
3 0
Hlo mate :-

Solution :-

☆ B 100 In 2 hrs
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I WILL GIVE BRAINLIEST
ryzh [129]

Answer:

See below. No image this time.

Step-by-step explanation:

1.

  • P(2, 8) → P'(-5, 1), which it went 7 units to the left, and 7 units down. Here is the equation: (x - 7, y - 7).

2.

  • R(-4, -9) → R'(-4, -2), which went 7 units up. Here is the equation: (x, y + 7).

3.

  • M(10, -3) → M'(3, 4), which went 7 units left, 7 units up. Here's the equation: (x - 7, y + 7).

4.

  • K(7, 11) → K'(0, 11), which went 7 units left. Here is the equation: (x - 7, y).
4 0
2 years ago
Kenny and johnny went to thr water park. Johnny bought a $1.50 ice cream bar. Write an expression to represent the amount the tw
blsea [12.9K]
2p+1.5=total spent I hope this helps

8 0
3 years ago
Anyone know how to do this?
IrinaVladis [17]
H(x) = x - 5

However, it had a domain of all real numbers such that x does not equal 3, since that would cause you to divide by 0. 
7 0
3 years ago
Read 2 more answers
In the diagram, point O is the center of the circle and AC¯¯¯¯¯ and BD¯¯¯¯¯ intersect at point E. If m∠AOB = 90° and
Romashka [77]
<span>m∠CED = </span><span>1/2(m∠AOB + </span><span><span>m∠COD)</span> = 1/2(90° + 16°) = 1/2(106°) = 53°</span>

7 0
3 years ago
Use the normal distribution of SAT critical reading scores for which the mean is 502 and the standard deviation is 116. Assume t
PSYCHO15rus [73]

Answer:

(a) 93.19%

(b) 267.3

Step-by-step explanation:

The population mean and standard deviation are given as 502 and 116 respectively.

Consider, <em>X</em> be the random variable that shows the SAT critical reading score is normally distributed.

(a) The percent of the SAT verbal scores are less than 675 can be calculated as:

P(X

Thus, the required percentage is 93.19%

(b)

The number of SAT verbal scores that are expected to be greater than 575 can be calculated as:

P(X>575)=P(\frac{x-502}{116}>\frac{575-502}{116}\\P(X>575)=P(Z>\frac{575-502}{116})\\P(X>575)=P(Z>0.6293)\\P(X>575)=0.2673

So,

Out of 1000 randomly selected SAT verbal scores, 1000(0.2673) = 267.3 are expected to have greater than 575.

8 0
3 years ago
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