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Brilliant_brown [7]
3 years ago
15

Which rate is equvalent to 55 miles per hour

Mathematics
1 answer:
GuDViN [60]3 years ago
3 0
Hlo mate :-

Solution :-

☆ B 100 In 2 hrs
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(1/2) (10)- (-12) -25
lianna [129]

Answer:

-8

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Historically, the mean yield of corn in the United States has been 120 bushels per acre with a standard deviation of 12. A surve
Illusion [34]

Answer:

z=\frac{125-120}{\frac{12}{\sqrt{40}}}=2.64    

P-value

Since is a two sided test the p value would be:  

p_v =2*P(z>2.64)=0.0082  

And the best answer would be

B 0.0082

Step-by-step explanation:

Data given and notation  

\bar X=125 represent the mean height for the sample  

\sigma=12 represent the population standard deviation

n=40 sample size  

\mu_o =120 represent the value that we want to test

\alpha represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is 120 or not, the system of hypothesis would be:  

Null hypothesis:\mu = 120  

Alternative hypothesis:\mu \neq 120  

If we analyze the size for the sample is > 30 and we know the population deviation so is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

z=\frac{125-120}{\frac{12}{\sqrt{40}}}=2.64    

P-value

Since is a two sided test the p value would be:  

p_v =2*P(z>2.64)=0.0082  

And the best answer would be

B 0.0082

4 0
3 years ago
4. Charlie is at a small airfield watching for the approach of a small plane with engine trouble. He sees the plane at an angle
Fofino [41]

check the picture below.


make sure your calculator is in Degree mode.

now, Charlie's eyes are 5.2' from the ground, however the distance from his eyes over the horizontal and the ground over the horizontal, is the same, so taking the tan(32°) at his eyes level will give that horizontal distance.

3 0
3 years ago
The first term of an Ap are x, 2x +1, and 5x+1 Find<br> x and the sum of the<br> l0 terms<br> first
bazaltina [42]

Answer:

145/2

Step-by-step explanation:

d=[2x+1-x] = [5x+1 -(2x+1)]

x+1=3x

x-3x=-1

-2x=-1

x=1/2

therefore first term is 1/2

second term is 2(1/2)+1= 2

common difference d is 2-1/2=3/2

sum of first n terms is n/2 [2a+(n-1)d] where n=10

sum of first 10 terms= 10/2[2×1/2+(10-1)3/2]

=5[1+(9)3/2] =5[1+27/2] = 5[29/2] =145/2

7 0
3 years ago
The top and bottom margins of a poster are each 15 cm and the side margins are each 10 cm. If the area of printed material on th
12345 [234]

Answer:

the dimension of the poster = 90 cm length and 60 cm  width i.e 90 cm by 60 cm.

Step-by-step explanation:

From the given question.

Let p be the length of the of the printed material

Let q be the width of the of the printed material

Therefore pq = 2400 cm ²

q = \dfrac{2400 \ cm^2}{p}

To find the dimensions of the poster; we have:

the length of the poster to be p+30 and the width to be \dfrac{2400 \ cm^2}{p} + 20

The area of the printed material can now be:  A = (p+30)(\dfrac{2400 }{p} + 20)

=2400 +20 p +\dfrac{72000}{p}+600

Let differentiate with respect to p; we have

\dfrac{dA}{dp}= 20 - \dfrac{72000}{p^3}

Also;

\dfrac{d^2A}{dp^2}= \dfrac{144000}{p^3}

For the smallest area \dfrac{dA}{dp }=0

20 - \dfrac{72000}{p^2}=0

p^2 = \dfrac{72000}{20}

p² = 3600

p =√3600

p = 60

Since p = 60 ; replace p = 60 in the expression  q = \dfrac{2400 \ cm^2}{p}   to solve for q;

q = \dfrac{2400 \ cm^2}{p}

q = \dfrac{2400 \ cm^2}{60}

q = 40

Thus; the printed material has the length of 60 cm and the width of 40cm

the length of the poster = p+30 = 60 +30 = 90 cm

the width of the poster = \dfrac{2400 \ cm^2}{p} + 20 = \dfrac{2400 \ cm^2}{60} + 20  = 40 + 20 = 60

Hence; the dimension of the poster = 90 cm length and 60 cm  width i.e 90 cm by 60 cm.

4 0
3 years ago
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