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il63 [147K]
3 years ago
11

Find the area of a circle with radius 6 cm. Use the value 3.14 for pi , and do not round your answer. Be sure to include the cor

rect unit in your answer.
Mathematics
1 answer:
ladessa [460]3 years ago
5 0

Answer:

113.04 cm

Step-by-step explanation:

Formula for Area of a Circle

A = πr²

A = π6²

6² = 36

36 x 3.14 is 113.04cm

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Please help ive been stuck in this question
kondaur [170]

Answer:

The choice A.

Step-by-step explanation:

sin= Opposite/ hypotenuse

\sin(30)  =  \frac{ \sqrt{15} }{x}  \\  \\ x = 2 \sqrt{15}

tan = opposite/adjacent

\tan(30)  =  \frac{ \sqrt{15} }{y}  \\  \\ y = 3 \sqrt{5}

I hope I helped you^_^

3 0
3 years ago
Ms. Emily buys a hat and gloves with a coupon for 30% off her entire purchase. The gloves cost $35 before the discount. Her bill
Gennadij [26K]
$44.80=($35+X)(1-0.3)

44.80 is the final total
You need to add the glove and hat cost to get a subtotal (35+x) and then multiply by what is left after the discount 30% off will leave 70% to pay, so in this equation 1-0.3 leaves 0.7 to multiply against the subtotal to get the total before tax of 44.80
7 0
3 years ago
3x-1. 5
Sav [38]
Simply plug in numbers!! (3x-1)(5)=55
15x-5=55
15x=60
x=4
hope this helps :)
5 0
3 years ago
Is it Giveaway time?<br><br><br> Why are you making me add more text :/
givi [52]
I hope it is giveaway time cause I need points
7 0
3 years ago
Read 2 more answers
A student walk 60m on a bearing
Katena32 [7]

Answer:

d = 234.6 m

Step-by-step explanation:

You can consider a system of coordinates with its origin at the beginning of the walk of the student.

When she start to walk, she is at (0,0)m. After her first walk, her coordinates are calculated by using the information about the incline and the distance that she traveled:

x_1=60cos28\°=52.97m\\\\y_1=60sin28\°=28.16m

she is at the coordinates (52.97 , 28.16)m.

Next, when she walks 180m to the east, her coordinates are:

(52.97+180 , 28.16)m = (232.97 , 28.16)m

To calculate the distance from the final point of the student to the starting point you use the Pythagoras generalization for the distance between two points:

d=\sqrt{(x-x_o)^2+(y-y_o)^2}\\\\x=232.97\\\\x_o=0\\\\y=28.16\\\\y_o=0\\\\d=\sqrt{(232.97-0)^2+(28.16-0)^2}m=234.6m

The displacement of the student on her complete trajectory was of 234.6m

8 0
3 years ago
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