2 years ago

Can you help me on his question

Mathematics

2 answers:

liraira [26]2 years ago

7 0

C 2 (-20)

He withdrew (took out) money twice.
That's -20 two times.

cestrela7 [59]2 years ago

3 0

How do you subtract an inter from another integer without using a number line or counters

You might be interested in

- 4x + 14 = -2(2x + 7)

expeople1 [14]

X=4
-4x4=-16+14=-2
2x4=8+7=15
-2 x 15=30

4 0

2 years ago

Find the definite integral from 0 to 1/16 of arcsin(8x)/sqrt(1-64x^2)dx

kolezko [41]

$\displaystyle\int_0^{1/16}\frac{\arcsin8x}{\sqrt{1-64x^2}}\,\mathrm dx$

First let $y=8x$ , so that $\mathrm dx=\dfrac{\mathrm dy}8$ to write the integral as

$\displaystyle\frac18\int_0^{1/2}\frac{\arcsin y}{\sqrt{1-y^2}}\,\mathrm dy$

Now recall that $(\arcsin y)'=\dfrac1{\sqrt{1-y^2}}$ , so substituting $z=\arcsin y$ should do the trick. The integral then becomes

$\displaystyle\frac18\int_0^{\pi/6}z\,\mathrm dz=\frac1{16}z^2\bigg|_{z=0}^{z=\pi/6}=\frac{\pi^2}{576}$

8 0

2 years ago

Simplify to create an equivalent expression. 8−4(−x+5) Choose 1 answer: A 4x−12 B −4x−12 C 4x+13 D 4x+5

Kaylis [27]

Answer:

A (4x-12)

Step-by-step explanation:

Still think of PEMDAS: 8-4(-x=5)

a) Multiply -4(-x + 5)

* -4(-x) = 4x (remember a neg x neg = pos)

* -4(5) = - 20

b) Now it reads = 8 +4x - 20

c) put all like terms together

* 8 - 20 = -12

6 0

2 years ago

Solve for t -18 = 6t

mihalych1998 [28]

-18 = 6t

Divide both sides by 6

-18/6 =6t/6

-3 = t

t= -3

5 0

4 months ago

Please could you help me with this. 132 people took a driving test. 80 people predicted they would pass. 64 people

GenaCL600 [577]

You have to do 64 x 3 and that equals 192 the answer is 192 if that was what you was asking! Respond if not!

3 0

1 year ago