Answer:
F. 6s > 4s +8
Step-by-step explanation:
From a reference point at the beginning of the track, Ward's car will be located 4s+8 feet down the track after s seconds. That is, it starts 8 feet down the track, and increases its distance by 4 feet every second.
From the same reference point, Heskey's car will be located 6s feet down the track after s seconds. Its distance starts from zero and is increasing at the rate of 6 feet every second.
For Heskey's distance to exceed Ward's distance you want ...
6s > 4s +8 . . . . . . matches choice F
Answer:
E(x) = 1.43 (Approx)
Step-by-step explanation:
Given:
Total number of camera = 7
Defective camera = 5
Sample selected = 2
Computation:
when x = 0
P(x=0) = 2/7 × 1/6 = 2/42
P(x=1) = [2/7 × 5/6] + [5/7 × 2/6] = 20/42
P(x=2) = 5/7 × 4/6 = 20/42
So,
E(x) = [0×2/42] + [1×20/42] + [2×20/42]
E(x) = 1.43 (Approx)
To find the same value as 3 x 1/10 you first have to solve 3 x 1/10
so how to do this is you have to make 3 into a fraction
so to make 3 into a fraction you can put 3 as the numerator and 1 as the denominator
so you multiply

so 3/10 has the same value as 3x1/10
HOPE THIS HELPS!!!
I don’t see any question. What is the question.