Continuous compounding is the mathematical limit that compound interest can reach.
It is the limit of the function A(1 + 1/n) ^ n as n approaches infinity. IN theory interest is added to the initial amount A every infinitesimally small instant.
The limit of (1 + 1/n)^n is the number e ( = 2.718281828 to 9 dec places).
Say we invest $1000 at daily compounding at yearly interest of 2 %. After 1 year the $1000 will increase to:-
1000 ( 1 + 0.02/365)^365 = $1020.20
with continuous compounding this will be
1000 * e^1 = $2718.28
Answer:
-2/11
Step-by-step explanation:
Answer:
35-7x
Step-by-step explanation:
Multiply parenthesis by -7
The answer is (d) first you solve 3/4
1. Take the two x-axis intersections.
For Q 31 it is:
x = -4 and x = 0
2. Reorganise the previous equations
x +4 = 0 and x = 0
3. Put the x side in brackets
x(x+4)
4. Done
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Q 32
x = -1
x = 5
x + 1 = 0
x - 5 = 0
(x+1)(x-5)
