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3 years ago

Solve the following 37/5+65/32

Mathematics

1 answer:

Temka [501]3 years ago

6 0

Hi there!

<u>Here's the answer;</u>

37/5+65/32 =

9.43125.

Hope this helps, if it does, please consider marking me brainiest! <3

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Using the standard 28/36 guidelines, what is the maximum mortgage payment allowed for someone with an annual salary of $60,750?

Anna11 [10]

$\frac{28}{36}$ rule says that 28 % of your total income should be spent on Housing finances and 36 % of your gross total income should be spend for Debts.

Annual Salary = $ 60,750

Maximum mortgage payment=28% of $ 60,750

$=\frac{28}{100} \times 60750=\frac{1701,00}{100}\\\\ =1701$

Maximum ,mortgage payment allowed for someone with an annual salary of $60,750= $ 1,701.00→→→Option (C)

7 0

3 years ago

Read 2 more answers

Brian bought 4 CDs that were each the same price. Including sales tax, he paid a total of $60.80 . Of that total, $3.60 was tax.

Yuliya22 [10]

Answer:

14.30

Step-by-step explanation:

$60.80 - $3.60 = 57.20/4 = 14.30

3 0

3 years ago

Mr Jones spent 156 to attend a college football game .twenty percent of this cost was for a parking pass.he spent the remainder

maks197457 [2]

Step One: Find 20% of 156
20% = .20
156 x .20 = 31.20

Step Two: Find the price of tickets

31.20 / 2 = 15.60

Final Answer: $15.60 per ticket

Hope this helps!

4 0

3 years ago

Can someone answer this?

Tcecarenko [31]

340.8 cm^2.

72+72+72+62.4+62.4=340.8cm^2.

6 0

3 years ago

The sum of first three terms of a finite geometric series is -7/10 and their product is -1/125. [Hint: Use a/r, a, and ar to rep

Alchen [17]

Ooh, fun

geometric sequences can be represented as
$a_n=a(r)^{n-1}$
so the first 3 terms are
$a_1=a$
$a_2=a(r)$
$a_2=a(r)^2$

the sum is -7/10
$\frac{-7}{10}=a+ar+ar^2$
and their product is -1/125
$\frac{-1}{125}=(a)(ar)(ar^2)=a^3r^3=(ar)^3$

from the 2nd equation we can take the cube root of both sides to get
$\frac{-1}{5}=ar$
note that a=ar/r and ar²=(ar)r
so now rewrite 1st equation as
$\frac{-7}{10}=\frac{ar}{r}+ar+(ar)r$
subsituting -1/5 for ar
$\frac{-7}{10}=\frac{\frac{-1}{5}}{r}+\frac{-1}{5}+(\frac{-1}{5})r$
which simplifies to
$\frac{-7}{10}=\frac{-1}{5r}+\frac{-1}{5}+\frac{-r}{5}$
multiply both sides by 10r
-7r=-2-2r-2r²
add (2r²+2r+2) to both sides
2r²-5r+2=0
solve using quadratic formula
for $ax^2+bx+c=0$
$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$
so
for 2r²-5r+2=0
a=2
b=-5
c=2

$r=\frac{-(-5) \pm \sqrt{(-5)^2-4(2)(2)}}{2(2)}$
$r=\frac{5 \pm \sqrt{25-16}}{4}$
$r=\frac{5 \pm \sqrt{9}}{4}$
$r=\frac{5 \pm 3}{4}$
so
$r=\frac{5+3}{4}=\frac{8}{4}=2$ or $r=\frac{5-3}{4}=\frac{2}{4}=\frac{1}{2}$

use them to solve for the value of a
$\frac{-1}{5}=ar$
$\frac{-1}{5r}=a$
try for r=2 and 1/2
$a=\frac{-1}{10}$ or $a=\frac{-2}{5}$

test each
for a=-1/10 and r=2
a+ar+ar²= $\frac{-1}{10}+\frac{-2}{10}+\frac{-4}{10}=\frac{-7}{10}$
it works

for a=-2/5 and r=1/2
a+ar+ar²= $\frac{-2}{5}+\frac{-1}{5}+\frac{-1}{10}=\frac{-7}{10}$
it works

both have the same terms but one is simplified

the 3 numbers are $\frac{-2}{5}$ , $\frac{-1}{5}$ , and $\frac{-1}{10}$

6 0

3 years ago