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Nutka1998 [239]
2 years ago
15

If the diameter of a youth baseball is 2. 8 inches and the diameter of an adult softball is 3. 8 inches, what is the approximate

difference in their volumes? use 3. 14 for pi. round to the nearest tenth. recall the formula sphere volume = four-thirds pi r cubed. 1. 0 cubic inch 17. 2 cubic inches 40. 2 cubic inches 137. 8 cubic inches.
Mathematics
1 answer:
Molodets [167]2 years ago
4 0

The approximate difference in their volumes is 17.2 cubic inches

<h3>How to determine the difference in the volume?</h3>

The given parameters are:

Diameter, d = 2.8

Diameter, D = 3.8

The radii are the half of the diameter.

So, we have:

r = 1.4

R = 1.9

The volume of the balls is then calculated using:

V = \frac{4}{3}\pi r^3

The difference is then represented as:

D = \frac{4}{3}\pi (R^3 - r^3)

Substitute known values

D = \frac{4}{3}* 3.14* (1.9^3 - 1.4^3)

Evaluate

D = 17.2

Hence, the approximate difference in their volumes is 17.2 cubic inches

Read more about volumes at:

brainly.com/question/1972490

#SPJ1

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Options A and D are correct. The pair of measurements that could be the dimensions of rectangle B is 6 cm by 1.5 cm and 18 cm by 4.5 cm.

For us to get a scale copy of the dimension, we need to first find the scale factor as shown;

Given the measure of rectangle A:

  • Length= 12cm
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To get all of the measurement pairs that could be the dimensions of Rectangle  B, we need to multiply the length and width by the same factor

Multiplying by 1/2

New length = 12 × 0.5 = 6cm

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Multiplying by 1.5

New length = 12 × 1.5 = 18cm

New width = 3 × 1.5 = 4.5cm

Hence 18cm by 4.5cm can be dimension of B

Learn more here: brainly.com/question/24759485

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Answer:

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