Answer:
The fourth option with x values of -3,-2,4 and 7 is a function of x.
Step-by-step explanation:
This is due to it having only one of each x value.
On the other tables, they have multiple values for an x value. This means that it is not a function
Answer:
5 terms: m, 4, 2, -7m, 6 are the terms in question.
Step-by-step explanation:
Note that terms here are separated from one another by either + or - signs.
m + 4 consists of two terms, since m and 4 are separated by the + operator.
2 - 7m are separated by the - operator, and so there are two terms here.
Completing the counting procedure, we get:
m (first term) + 4 (second term) + 2 (third term -7m (fourth term) + 6 (fifth term).
So, if we do NOT combine like terms, we have five (5) terms altogether.
If we DO combine like terms, we end up with two (2) terms:
m -7m + 4 + 2 + 6, or -6m + 12, or two (2) terms.
If you plug in the x-coordinate into your equation for the line, you get
y = -3(4)/4 + 3
y = -3 + 3
y = 0
Answer:
18x^5y
Step-by-step explanation:
Divide 36 by 2 first : 18
since you are dividing, you subtract the exponents:
x^8 - x^3= x^5
y^4-y^3= y^1 but you usually just write y
![z=2x^4+8x \\ dz=(8x^3+8)\ dx=8(x^3+1)\ dx \\ \int\limits^0_{-1} {(2x^4+8x)^3*(4x^3+4)} \, dx =4* \int\limits^0_{-6} { \dfrac{z^3}{2}} \, dz \\ = 2* \left[\begin{array}{ccc} \dfrac{z^4}{4}\end{array}\right] ^0_{-6}= \left[\begin{array}{ccc} \dfrac{z^4}{2}\end{array}\right] ^0_{-6}=0-648=-648](https://tex.z-dn.net/?f=%20z%3D2x%5E4%2B8x%20%5C%5C%0Adz%3D%288x%5E3%2B8%29%5C%20dx%3D8%28x%5E3%2B1%29%5C%20dx%20%5C%5C%0A%0A%20%5Cint%5Climits%5E0_%7B-1%7D%20%7B%282x%5E4%2B8x%29%5E3%2A%284x%5E3%2B4%29%7D%20%5C%2C%20dx%20%3D4%2A%20%5Cint%5Climits%5E0_%7B-6%7D%20%7B%20%5Cdfrac%7Bz%5E3%7D%7B2%7D%7D%20%5C%2C%20dz%20%5C%5C%0A%3D%202%2A%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%20%5Cdfrac%7Bz%5E4%7D%7B4%7D%5Cend%7Barray%7D%5Cright%5D%20%5E0_%7B-6%7D%3D%0A%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%20%5Cdfrac%7Bz%5E4%7D%7B2%7D%5Cend%7Barray%7D%5Cright%5D%20%5E0_%7B-6%7D%3D0-648%3D-648)