I will assume that by "Evaluate 8(7x--3) when x=9" you meant:
"Evaluate 8(7x-3) when x=9."
First, substitute 9 for x in 7x-3: 7(9)-3 = 60. Rewrite the problem as:
8(60). Multiply. Answer: 480
Answer: 4a16b4c12
Step-by-step explanation:
Hey there!
First, we see that it's already written in slope intercept, y = mx + b where m is the slope and b is the y intercept, we just need to simplify the like terms on the right. We have:
y = 12x-5x-2
y = 7x - 2
Now that we have it in slope intercept form, whenever we have an x intercept, since it is crossing the x axis, there's no y value. We plug in 0 for y:
0 = 7x - 2
2 = 7x
2/7 = x
The x intercept is (2/7, 0)
Hope this helps!
