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grigory [225]
4 years ago
14

Find f(-10) F(x) =7x-5 A= -75 B=-65 C=65 D=90

Mathematics
1 answer:
STALIN [3.7K]4 years ago
8 0

Answer:

-75

Step-by-step explanation:

f(-10) = 7(-10) - 5

f(-10) = -70 - 5

f(-10) = -75

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Please help asap 30 pts
riadik2000 [5.3K]

The inequality:

0.19x+75\geq100\qquad|-75\\\\0.19x\geq25\qquad|:0.19\\\\x\geq\dfrac{25}{0.19}\approx132

<h3>Answer: d. x ≥ 132</h3>
3 0
3 years ago
Why does 3x - 7 = 3x + 5 have no solution?
Sladkaya [172]

hi

because it lead to mathematical nonsense

3x-7  = 3x+5

3x-7 -3x-5 = 0

    -7-5 = 0

    -12 =0  

-12 = 0 is just not possible, so 3x-7 = 3x +5  has no solution.

7 0
2 years ago
What do you know about the slope of parallel lines?
musickatia [10]
The slope formula is amount risen over amount run. Look up the formula for a better demonstration. Also, it determines how steep a line is. Brainliest pls?

8 0
3 years ago
Please help! Brainly list in return thank you so much..
olga nikolaevna [1]

Answer:

The student is missing the fact that RQ must be congruent to UT  for the triangles to be congruent, according to the property.

6 0
2 years ago
The Edward James Toy Company uses a Kanban system to make plastic wheels that are a component of several toys. The waiting time
pickupchik [31]

Answer:

N_c \approx 5.0

Step-by-step explanation:

From the question we are told that:

Waiting time for a container of the wheels during production T_w=0.25day

Average processing time is T_a=0.15 day per container

Wheel per container N_w=200

Total wheel per day D=2000

Policy variable of X=5%  

Generally the equation for Total number of container N_c is mathematically given by

N_c=DT(\frac{1+X}{N_w} )

Where

Total time T=T_w+T_a

T=0.15+0.25

Therefore

N_c=DT(\frac{1+X}{N_w} )

N_c=2000*0.40(\frac{1+0.5}{200} )

N_c=(\frac{840}{200} )

N_c=4.2

N_c \approx 5.0

Therefore the number of Kanban containers needed for the wheels is

N_c \approx 5.0

3 0
3 years ago
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