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N76 [4]
3 years ago
5

Josh rode his bike 11.4 miles. Claire rode her bike 6.8 miles. Which explains how mental math can be used to find how much farth

er Josh rode than Claire?
Mathematics
2 answers:
rosijanka [135]3 years ago
6 0

Answer:

4.6 miles

Step-by-step explanation:

B. Add 0.2 to 6.8 to get 7. Subtract 7 from 11.4 to get 4.4. Then add 0.2 to 4.4 to get 4.6. Josh rode 4.6 miles farther than Claire.

Alex3 years ago
4 0
11.4 - 6.8 = 4.6. He rode 4.6 more miles than Claire
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I need help I forgot all about this and I would appreciate it!
miskamm [114]

Answer:

$3.75

Step-by-step explanation:

You only have to multiply 3 pounds by the $1.25 to get the cost.

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SOMEONE HELP MEEEEEE 75 POINTS TO THE PERSON THAT HELPS
Tresset [83]

Answer:

Part 1) 9x-7y=-25

Part 2) 2x-y=2

Part 3) x+8y=22  

Part 4) x+8y=35

Part 5) 3x-4y=2

Part 6) 10x+6y=39

Part 7) x-5y=-6

Part 8)

case A) The equation of the diagonal AC is x+y=0

case B) The equation of the diagonal BD is x-y=0

Step-by-step explanation:

Part 1)

step 1

Find the midpoint

The formula to calculate the midpoint between two points is equal to

M=(\frac{x1+x2}{2},\frac{y1+y2}{2})

substitute the values

M=(\frac{2-6}{2},\frac{-3+5}{2})

M=(-2,1)

step 2

The equation of the line into point slope form is equal to

y-1=\frac{9}{7}(x+2)\\ \\y=\frac{9}{7}x+\frac{18}{7}+1\\ \\y=\frac{9}{7}x+\frac{25}{7}

step 3

Convert to standard form

Remember that the equation of the line into standard form is equal to

Ax+By=C

where

A is a positive integer, and B, and C are integers

y=\frac{9}{7}x+\frac{25}{7}

Multiply by 7 both sides

7y=9x+25

9x-7y=-25

Part 2)

step 1

Find the midpoint

The formula to calculate the midpoint between two points is equal to

M=(\frac{x1+x2}{2},\frac{y1+y2}{2})

substitute the values

M=(\frac{1+5}{2},\frac{0-2}{2})

M=(3,-1)

step 2

Find the slope

The slope between two points is equal to

m=\frac{-2-0}{5-1}=-\frac{1}{2}

step 3

we know that

If two lines are perpendicular, then the product of their slopes is equal to -1

Find the slope of the line perpendicular to the segment joining the given points

m1=-\frac{1}{2}

m1*m2=-1

therefore

m2=2

step 4

The equation of the line into point slope form is equal to

y-y1=m(x-x1)

we have

m=2 and point (1,0)

y-0=2(x-1)\\ \\y=2x-2

step 5

Convert to standard form

Remember that the equation of the line into standard form is equal to

Ax+By=C

where

A is a positive integer, and B, and C are integers

y=2x-2

2x-y=2

Part 3)

In this problem AB and BC are the legs of the right triangle (plot the figure)

step 1

Find the midpoint AB

M1=(\frac{-5+1}{2},\frac{5+1}{2})

M1=(-2,3)

step 2

Find the midpoint BC

M2=(\frac{1+3}{2},\frac{1+4}{2})

M2=(2,2.5)

step 3

Find the slope M1M2

The slope between two points is equal to

m=\frac{2.5-3}{2+2}=-\frac{1}{8}

step 4

The equation of the line into point slope form is equal to

y-y1=m(x-x1)

we have

m=-\frac{1}{8} and point (-2,3)

y-3=-\frac{1}{8}(x+2)\\ \\y=-\frac{1}{8}x-\frac{1}{4}+3\\ \\y=-\frac{1}{8}x+\frac{11}{4}

step 5

Convert to standard form

Remember that the equation of the line into standard form is equal to

Ax+By=C

where

A is a positive integer, and B, and C are integers

y=-\frac{1}{8}x+\frac{11}{4}

Multiply by 8 both sides

8y=-x+22

x+8y=22  

Part 4)

In this problem the hypotenuse is AC (plot the figure)

step 1

Find the slope AC

The slope between two points is equal to

m=\frac{4-5}{3+5}=-\frac{1}{8}

step 2

The equation of the line into point slope form is equal to

y-y1=m(x-x1)

we have

m=-\frac{1}{8} and point (3,4)

y-4=-\frac{1}{8}(x-3)

y=-\frac{1}{8}x+\frac{3}{8}+4

y=-\frac{1}{8}x+\frac{35}{8}

step 3

Convert to standard form

Remember that the equation of the line into standard form is equal to

Ax+By=C

where

A is a positive integer, and B, and C are integers

y=-\frac{1}{8}x+\frac{35}{8}

Multiply by 8 both sides

8y=-x+35

x+8y=35

Part 5)  

The longer diagonal is the segment BD (plot the figure)  

step 1

Find the slope BD

The slope between two points is equal to

m=\frac{4+2}{6+2}=\frac{3}{4}

step 2

The equation of the line into point slope form is equal to

y-y1=m(x-x1)

we have

m=\frac{3}{4} and point (-2,-2)

y+2=\frac{3}{4}(x+2)

y=\frac{3}{4}x+\frac{6}{4}-2

y=\frac{3}{4}x-\frac{2}{4}

step 3

Convert to standard form

Remember that the equation of the line into standard form is equal to

Ax+By=C

where

A is a positive integer, and B, and C are integers

y=\frac{3}{4}x-\frac{2}{4}

Multiply by 4 both sides

4y=3x-2

3x-4y=2

Note The complete answers in the attached file

Download docx
3 0
3 years ago
Solve for x. mx2 + y e = b
m_a_m_a [10]
X=(b/2m)*y-e is the answer I believe.
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vovangra [49]

Answer:

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Step-by-step explanation:

A=1/2h(a+b)

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a+b=A/(h/2)

a+b=(A/1)(2/h)

a+b=2A/h

b=2A/h-a

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Answer:

5(15+4)

Step-by-step explanation:

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