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AURORKA [14]
3 years ago
11

Part A

Mathematics
1 answer:
masya89 [10]3 years ago
8 0

Answer:

Part A) The area of triangle i is 3\ cm^{2}

Part B) The total area of triangles i and ii is 6\ cm^{2}

Part C) The area of rectangle i is 20\ cm^{2}

Part D) The area of rectangle ii is 32\ cm^{2}

Part E) The total area of rectangles i and iii is 40\ cm^{2}

Part F) The total area of all the rectangles is 72\ cm^{2}

Part G) To find the surface area of the prism, we need to know only the area of triangle i and the area of rectangle i and the area of rectangle ii, because the area of triangle ii is equal to the area of triangle i and the area of rectangle iii is equal to the area of rectangle i

Part H) The surface area of the prism is 78\ cm^{2}

Part I) The statement is false

Part J) The statement is true

Step-by-step explanation:

Part A) What is the area of triangle i?

we know that

The area of a triangle is equal to

A=\frac{1}{2} (b)(h)

we have

b=4\ cm

h=1.5\ cm

substitute

A=\frac{1}{2} (4)(1.5)

Ai=3\ cm^{2}

Part B) Triangles i and ii are congruent (of the same size and shape). What is the total area of triangles i and ii?

we know that

If Triangles i and ii are congruent

then

Their areas are equal

so

Aii=Ai

The area of triangle ii is equal to

Aii=3\ cm^{2}

The total area of triangles i and ii is equal to

A=Ai+Aii

substitute the values

A=3+3=6\ cm^{2}

Part C) What is the area of rectangle i?

we know that

The area of a rectangle is equal to

A=(b)(h)

we have

b=2.5\ cm

h=8\ cm

substitute

Ai=(2.5)(8)

Ai=20\ cm^{2}

Part D) What is the area of rectangle ii?

we know that

The area of a rectangle is equal to

A=(b)(h)

we have

b=4\ cm

h=8\ cm

substitute

Aii=(4)(8)

Aii=32\ cm^{2}

Part E) Rectangles i and iii have the same size and shape. What is the total area of rectangles i and iii?

we know that

Rectangles i and iii are congruent (have the same size and shape)

If rectangles i and iii are congruent

then

Their areas are equal

so

Aiii=Ai

The area of rectangle iii is equal to

Aiii=20\ cm^{2}

The total area of rectangles i and iii is equal to

A=Ai+Aiii

substitute the values

A=20+20=40\ cm^{2}

Part F) What is the total area of all the rectangles?

we know that

The total area of all the rectangles is

At=Ai+Aii+Aiii

substitute the values

At=20+32+20=72\ cm^{2}

Part G) What areas do you need to know to find the surface area of the prism?

To find the surface area of the prism, we need to know only the area of triangle i and the area of rectangle i and the area of rectangle ii, because the area of triangle ii is equal to the area of triangle i and the area of rectangle iii is equal to the area of rectangle i

Part H) What is the surface area of the prism? Show your calculation

we know that

The surface area of the prism is equal to the area of all the faces of the prism

so

The surface area of the prism is two times the area of triangle i plus two times the area of rectangle i plus the area of rectangle ii

SA=2(3)+2(20)+32=78\ cm^{2}

Part I) Read this statement: “If you multiply the area of one rectangle in the figure by 3, you’ll get the total area of the rectangles.” Is this statement true or false? Why?

The statement is false

Because, the three rectangles are not congruent

The total area of the rectangles is 72\ cm^{2} and if you multiply the area of one rectangle by 3 you will get 20*3=60\ cm^{2}

72\ cm^{2}\neq 60\ cm^{2}

Part J) Read this statement: “If you multiply the area of one triangle in the figure by 2, you’ll get the total area of the triangles.” Is this statement true or false? Why?

The statement is true

Because, the triangles are congruent

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The ratio for sine is opposite/hypotenuse.  This means the side opposite the angle is √3 and the hypotenuse is 5.  Using the Pythagorean theorem to find the adjacent side,
(√3)² + A² = 5²
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This means that cos a = adjacent/hypotenuse = (√22)/5 and tan a = opposite/adjacent = (√3)/(√22) = (√66)/22.
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(√5)²+1² = H²
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√6 = H
This means that sin a = opposite/hypotenuse = (√5)/(√6) = (√30)/6 and cos a = adjacent/hypotenuse = 1/(√6) = (√6)/6.
D)  The ratio for cosine is adjacent/hypotenuse; this means that the side adjacent the angle is 4 and the hypotenuse is 5.  Using the Pythagorean theorem to find the side opposite the angle, p:
4²+p²=5²
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p²=9
p=3
This means that sin a = opposite/hypotenuse = 3/5 and tan a = opposite/adjacent = 3/4.
E)  The ratio for tangent is opposite/adjacent;; this means that the side opposite the angle is 5 and the side adjacent the angle is 1.  Using the Pythagorean theorem to find the hypotenuse,
5²+1²=H²
25+1=H²
26=H²
√26 = H
This means that sin a = opposite/hypotenuse = 5/(√26) = (5√26)/26 and cos a = adjacent/hypotenuse = 1/(√26) = √26/26.
F) 0.8 = 8/10; The ratio for cosine is adjacent/hypotenuse.  This means that the side adjacent the angle is 8 and the hypotenuse is 10.  Using the Pythagorean theorem to find the side opposite the angle, p:
8²+p² = 10²
64+p² = 100
p² = 36
p=6
This means that sin a = opposite/hypotenuse = 6/10 = 3/5 and tan a = opposite/adjacent = 6/8 = 3/4.
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