Answer:
0.410
Step-by-step explanation:
We are predicting exam 2 scores from exam 1 scores so the dependent variable y is exam 2 scores and independent variable is exam 1 scores x.
The regression equation is
y=a+bx
Where y is exam 2 scores and x is exam 1 scores.
We are given that
correlation coefficient=r=0.6.
Mean and standard deviation of x are xbarx=85 and Sx=12.
Mean and standard deviation of y are xbary=82 and Sy=8.2.
The slope b for this scenario can be found as




Thus, the slope of the regression equation for predicting Exam 2 scores from Exam 1 scores is 0.410.
Answer:
Usually, we would subtract the area of a smaller inner shape from the area of a larger outer shape in order to find the area of the shaded region.
Step-by-step explanation:
Answer:
Therefore (2.30-0.03747)= 2.2625 M of HI remains from an initial concentration of 2.30 M after 4.5 hours.
Step-by-step explanation:
second order reaction: The rate of reaction proportional to the square of the concentration of reactant.
For second order reaction

K is rate constant = 1.6×10⁻³M⁻¹hr⁻¹
a = initial concentration of reactant = 2.30 M
a-x = concentration of reactant after t h
t = time = 4.5 h
Putting the values in the above equation,





Therefore (2.30-0.03747)= 2.2625 M of HI remains from an initial concentration of 2.30 M after 4.5 hours.
685-85=600
1 year =12 months
12 multiply by 2 =24
600 divided by 24=25
answer=25
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