the value is
1.2r-11.3r=40
-10.Ir=40
r=40/-10.1
r=-0.2525
hope this helps :):):)
Answer:
incorrect because the square area would be 440
Step-by-step explanation:
Answer:
They have the same x-value
f(x) has the greater minimum
Step-by-step explanation:
To find the vertex of a second degree equation, in this case the minimum value, we can use the following equation:
x = -b / 2a
Remember that a second degree equation has the following form:
ax^2 + bx + c
so a = 1, b = -8 and c = 7. Now you have to substitute in the previous equation
x = - (-8) / 2(1)
x = 8 / 2
x = 4
This means that the two functions have the same x-value.
The y value of f(x) would be
f(4) = (4)^2 - 8(4) + 7
f(4) = 16 - 32 + 7
f(4) = -9
So the vertex, or minimun value of f(x) would be at the point (4, -9).
The vertex, or minimun value of g(x) is at the point (4, -4).
So f(x) has a minimum value of -9 and g(x) a minimum value of -4.
Answer: They are parallel
Step-by-step explanation:
If two lines are parallel , then they must have the same slope and if two lines are perpendicular , the product of their slope must be -1.
To check this , we must calculate the slope of the two lines given.
Slope = 
from the first point
= 2
= 1
= 5
= -1
substituting the values
slope 1 = 1 - 2 / -3 - 5
slope1 = -1 / -8
slope 1 = 1/8
Using the same format to calculate the slope of the second line
= -2
= 0
= -1
= 15
slope 2 = 0 - (-2) / 15 - (-1)
slope 2 = 2/16
slope 2 = 1/8
Since slope 1 = slope 2 , this implies that the lines are parallel
