Question

Point D is the incenter of triangle BCA. If m∠FDG = 136°, what is the measure of ∠FHG?

Answer 1

Given:

Point D is incenter of ΔBCA.

m∠FDG = 136°

To find:

The measure of ∠FHG

Solution:

Angle subtended by the arc at the center is twice that subtended on the remain part of the circle.

$\Rightarrow m\angle FDG = 2 m\angle FHG$

Divided by 2 on both sides.

$\Rightarrow \frac{1}{2} m\angle FDG = \frac{1}{2} \times 2 m\angle FHG$

$\Rightarrow \frac{1}{2} m\angle FDG = m\angle FHG$

Substitute m∠FDG = 136°

$\Rightarrow \frac{1}{2} (136^\circ)= m\angle FHG$

$\Rightarrow 68^\circ= m\angle FHG$

The measure of ∠FHG is 68°.

Answer 2

Answer:

the correct answer is 68

Step-by-step explanation:

you just have to divide 136 by 2 and you will get 68