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4 years ago

Active transport makes it possible for cells to:______.

Biology

1 answer:

luda_lava [24]4 years ago

8 0

Answer:

e. All of the above are correct.

Explanation:

Active transport is a type of transport in living systems in which molecules/ions/substances are moved or transported against their concentration gradient i.e. from a region where the substance is LOW to a region which it is HIGH, across a membrane. Since molecules are transported across a memembrane against their concentration gradient, an energy input in form of ATP is needed to do so.

Active transport is used in living systems to transport out secretory products and waste material against concentration gradients, take up nutrients from the environment against concentrations gradients etc. Since ions are substance moved by active transport from a low region to high region, there is an imbalance in the intracellular concentration of ions, such as Na, K etc.

Since there is no equilibrium in the concentration of ions on opposite sides of the membrane, an electric potential is formed across the membrane i.e. one part of the membrane will be more positively charged than the other.

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How does secondary succession differ from primary succession?

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Primary succession need soil, when secondary succession uses remainder soil

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4 years ago

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Found in both plant cells and animal cells, the________________surrounds and protects the cell, and allows certain chemicals to

Nina [5.8K]

Answer:

cell wall

Explanation:

The cell wall is the protective, semi-permeable outer layer of a plant cell

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3 years ago

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Imagine that you attempted to recreate Mendel's work with garden peas. You began by crossing true breeding violet-flowered, tall

salantis [7]

Answer:

(a) 90

(b) 30

(d) 10

F2 data for stem length (tall:dwarf) is consistent with Mendel's law of segregation.

F2 data for stem length (tall:dwarf) and flower color (violet:white) is consistent with Mendel's law of independent assortment

Explanation:

The F2 phenotypes are supposed to be in 9:3:3:1 according to Mendelian law. The total number of F2 progeny is: 80 + 36 + 39 + 5 = 160

(a) Hence, the expected number of tall, violet plants will be:

9/16 x 160 = 90

(b) Expected number of tall, white plants will be:

3/16 x 160 = 30

(d) Expected number of dwarf, white plants will be:

1/16 x 160 = 10.

Total number of tall F2 plants = 80 + 36 = 116

Total number of dwarf F2 plants = 39 + 5 = 44

Expected ratio of tall:dwarf plants according to Mendel = 3:1

Expected number of tall plants = 3/4 x 160 = 120

Expected number of dwarf plants = 1/4 x 160 = 40

Chi square $X^2$

= $\frac{(observed frequency - expected frequency)^2}{expected frequency}$

$X^2$ for tall = $\frac{(116 - 120)^2}{120}$

= 0.1333

$X^2$ for dwarf = $\frac{(44 - 40)^2}{40}$

= 0.40

Total $X^2$ = 0.1333 + 0.4

0.5333

Degree of freedom = n - 1

2 - 1 = 1

Tabulated $X^2$ (α = 0.05) = 3.841

Since the tabulated $X^2$ is more than the calculated $X^2$ , the hypothesis that the F2 data for stem length (tall:dwarf) is consistent with Mendel's law of segregation is accepted.

Observed Expected $X^2$

tall, violet flowers 80 90 $\frac{(80-90)^2}{90} = 1.11$

tall, white flowers 36 30 $\frac{(36-30)^2}{30} = 1.2$

dwarf, violet flowers 39 30 $\frac{(39-30)^2}{30} = 2.7$

dwarf, white flowers 5 10 $\frac{(5-10)^2}{10} = 2.5$

Total 160 160 7.51

Degree of freedom = 4 - 1 = 3

Tabulated $X^2$ (α = 0.05) = 7.815

The tabulated $X^2$ value is more than the calculated $X^2$ value. Hence, F2 data for stem length (tall:dwarf) and flower color (violet:white) is consistent with Mendel's law of independent assortment.

3 0

3 years ago

In sequential test, there is typically a loss in specificity. <br> a. True <br> b. False

maks197457 [2]

I'm pretty sure that's false.

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4 years ago

Can any genius help me with this?? its my last question.

Marina86 [1]

Answer:I think it’s

Explanation:

I think it’s