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Ivanshal [37]
3 years ago
9

Which expression defines the given series for seven terms? –3 + (–1) + 1 + . . .

Mathematics
2 answers:
S_A_V [24]3 years ago
7 0
-3+(-1)+1+...\\\\a_1=-3;\ a_2=-1;\ a_3=1\\\\It's\ an\ arithmetic\ sequence\ where\ the\ common\ difference\\is\ equal\ d=a_2-a_1=-1-(-3)=-1+3=2.\\\\a_n=a_1+(n-1)d\\\\a_n=-3+(n-1)\cdot2=-3+2n-2=2n-5\\\\Answer:\boxed{\sum\limits_{n=1}^7(2n-5)}\to\fbox{a.}
sergeinik [125]3 years ago
6 0

Answer: \sum^{7}_{n=1}(2n-5)

Step-by-step explanation:

Given: The first term of the series a= -3

The second term of the series a_2= -1

The third term of the series a_3= 1

The common difference=d=a_3-_a_2=a_2-a_1=2

Now, the nth term of this series will be given by :-

a_n=a+d(n-1)\\\\\Rightarrow\ a_n=-3+2(n-1)\\\\\Rightarrow\ a_n=-3+2n-2\\\\\Rightarrow\ a_n=2n-5

Hence, the expression defines the given series for seven terms will be

\sum^{7}_{n=1}(2n-5)

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