Answer:
B. No, this distribution does not appear to be normal
Step-by-step explanation:
Hello!
To observe what shape the data takes, it is best to make a graph. For me, the best type of graph is a histogram.
The first step to take is to calculate the classmark`for each of the given temperature intervals. Each class mark will be the midpoint of each bar.
As you can see in the graphic (2nd attachment) there are no values of frequency for the interval [40-44] and the rest of the data show asymmetry skewed to the left. Just because one of the intervals doesn't have an observed frequency is enough to say that these values do not meet the requirements to have a normal distribution.
The answer is B.
I hope it helps!
X would be 63, Y would be 27
A straight line is 180 degrees. 180-117=63
To find Y, since we know it is a 90 degree angle do 90-63 which is 27.
<span>V/7= 22
Multiply 7 on both sides
Final Answer: V = 154</span>
F(-2)+g(5) = 3(-2) -1 + (-5) + 6
f(-2)+g(5) = -6 -1 - 5 + 6
f(-2)+g(5) = -6
Answer:
Mixed numbers[edit]. A mixed numeral ( also called a mixed fraction or mixed number) is a traditional denotation of the sum ...