Which Call of Duty game is the best?

Describe the tools that are required to accomplish each step in the data management process.

RideAnS [48]

Answer: The tools which are required to accomplish each step in the data management process are:

1. Cloud Data Management tools.

2. Master Data Management (MDM) tools.

3. Reference Data Management (RDM) tools.

4. ETL tools.

5. Data visualization and analytics tools

Explanation:

Cloud Data Management tools with the help of various API's are able to connect multiples system with their data to the cloud. examples are amazon cloud, google API cloud.

MDM tools are used for creation and maintenance of reference data. example are Profisee

RDM tools is used with the MDM tools and are use to define the businesss processes over the reference data. Examples are Collibra.

ETL tools helps to load data of an organisation to data warehouses after transformation and testing the data pipeline constituting the data from different databases.

Data visualization analytics tools helps to extract and generate report from the big sets of data which can help an organisation to take business decisions.

6 0

3 years ago

Read 2 more answers

DO, of X isvvvvvvvvvvvvvvv

dem82 [27]

Huh ? I don’t understand the question

8 0

3 years ago

Write a method that prints on the screen a message stating whether 2 circles touch each other, do not touch each other or inters

beks73 [17]

Answer:

The method is as follows:

public static void checkIntersection(double x1, double y1, double r1, double x2, double y2, double r2){

double d = Math.sqrt(Math.pow((x1 - x2),2) + Math.pow((y1 - y2),2));

if(d == r1 + r2){

System.out.print("The circles touch each other"); }

else if(d > r1 + r2){

System.out.print("The circles do not touch each other"); }

else{

System.out.print("The circles intersect"); }

}

Explanation:

This defines the method

public static void checkIntersection(double x1, double y1, double r1, double x2, double y2, double r2){

This calculate the distance

double d = Math.sqrt(Math.pow((x1 - x2),2) + Math.pow((y1 - y2),2));

If the distance equals the sum of both radii, then the circles touch one another

if(d == r1 + r2){

System.out.print("The circles touch each other"); }

If the distance is greater than the sum of both radii, then the circles do not touch one another

else if(d > r1 + r2){

System.out.print("The circles do not touch each other"); }

If the distance is less than the sum of both radii, then the circles intersect

else{

System.out.print("The circles intersect"); }

}

6 0

3 years ago

Write the class "Tests". Ensure that it stores a student’s first name, last name, all five test scores, the average of those 5 t

zhannawk [14.2K]

Answer:

The following assumption will be made for this assignment;

If average score is greater than 75, the letter grade is A

If average score is between 66 and 75, the letter grade is B

If average score is between 56 and 65, the letter grade is C

If average score is between 46 and 55, the letter grade is D
If average score is between 40 and 45, the letter grade is E
If average score is lesser than 40, the letter grade is F

The program is written in Java and it uses comments to explain difficult lines. The program is as follows

import java.util.*;

public class Tests

{

public static void main(String [] args)

{

//Declare variables

Scanner input = new Scanner(System.in);

String firstname, lastname;

//Prompt user for name

System.out.print("Enter Lastname: ");

lastname = input.next();

System.out.print("Enter Firstname: ");

firstname = input.next();

char grade;

//Declare Array

int[] Scores = new int[5];

//Initialize total scores to 0

int total = 0;

//Decalare Average

double average;

//Prompt user for scores

for(int i =0;i<5;i++)

{

System.out.print("Enter Score "+(i+1)+": ");

Scores[i] = input.nextInt();

//Calculate Total Scores

total+=Scores[i];

}

//Calculate Average

average = total/5.0;

//Get Letter Grade

if(average>75)

{

grade = 'A';

}

else if(average>65)

{

grade = 'B';

}

else if(average>55)

{

grade = 'C';

}

else if(average>45)

{

grade = 'D';

}

else if(average>40)

{

grade = 'E';

}

else

{

grade = 'F';

}

//Print Student Results

System.out.print("Fullname: "+lastname+", "+firstname);

System.out.print('\n');

System.out.print("Total Scores: "+total);

System.out.print('\n');

System.out.print("Average Scores: "+average);

System.out.print('\n');

System.out.print("Grade: "+grade);

}

See Attachment for .java file

Download java

7 0

4 years ago

What is the rate constant at 25.0 ∘c based on the data collected for trial b?

Alecsey [184]

<h2>Answer: </h2>

acetone + I2 + HCl ---> iodated acetone

Equation:

rate = k * [acetone]^x * [I2]^y * [HCl]^z

Once we know x, y, z, we can plug in any of the trials A->D and determine k NOTE: We can't use run E because temperature has an effect on rate. E was run at a different temperature.

The first thing to note is that do NOT have concentrations. We have volumes at a given molarity.

Table:

.001M I2.. ..050M HCl.. .1.0M acetone.. .water.. temp..time.. total vol

.. ....mL.. ... ... .. .mL.. .. ... .. .. mL.. .. .. .. ..mL.. ..°C.. .sec.. .. .. .L

A.. ...5.. .. .. .. .. ..10.. .. .. .. .. ..10.. .. .. .. ..25.. .. .25.. .130.. .. 0.05

B.. ..10.. .. .. ... .. 10.. .. .. ... .. .10.. .. .. ... ..20.. . .25.... 249.. ..0.05

C.. . 10.. .. .. .. .. .20.. .. .. .... .. 10.. .. ... ... .10... ..25.. ..128... .0.05

D.. . 10.. ... .. ... ..10.. .. ... .. ... 20.. .. .. .. .. 10.. .. 25.. ..131.. ..0.05

E.. ..10.. ... .. ... ..10.. ... ... ... ..10.. ... .. ... .20.. .. 42.8.. .38.. ..0.05

We can translate that into molarity in solution using this formula. (molarity pure ingredient * mL used / 1000 / total volume in liters)

.. .. ..I2.. .... HCl.. acetone.. temp.. ..rxn time

.. .. ..M.. .. ...M.. .... .M.. .... ..°C.. .. .. sec

A.. 0.0001.. 0.01..... 0.2.. .... .25... .... .130

B.. 0.0002.. 0.01.. .. 0.2.. .. .. 25.. .. .. .249

C.. 0.0002.. 0.02.. .. 0.2.. .. .. 25.. .. .. .128

D.. 0.0002.. 0.01.. .. 0.4.. .. . .25.. ... ...131

E.. 0.0002.. 0.01.. .. 0.2.. . ....42.8.. .. .. 38

From runs B and D, we can see that rate dropped by half .

As [I2] and [HCl] were held constant and [acetone] was doubled.

This means x=-1 in this equation

Rate = k * [acetone]⁻¹ * [I2]^y * [HCl]^z

Rate = k * [I2]^y * [HCl]^z

From runs A and B

[I2] doubles

[HCl] remains the same

[acetone] remains the same

rate doubles as [I2] doubles, rate doubles

y = 1 rate = k * [acetone]⁻¹ * [I2]¹ * [HCl]^z

And from runs B and C, we can see that , As [HC] doubles, (all else equal) the rate halves.

Z = -1

Rate = k * [I2] / ([acetone] * [HCl])

Rearranging

k = rate * [acetone] * [HCl] / [I2]

From any experimental run (A-D), we can calculate k.

using A to calc k... ..k = 2600 M²/sec

using B to calc k... . k = 2490 M²/sec

using C to calc k... . k = 2560 M²/sec

using D to calc k... . k = 2620 M²/sec

NOTE.. the problem statement said to use the data from run B to calc k.

Hence Final Answer:

k = 2490 M²/sec

4 0

4 years ago