That’s cool I’ll play the game tonight if I can
Answer:
#include <iostream>
using namespace std;
int main()
{
string str;
cout<<"Enter the string: ";
cin>>str;
for(int i=0;str[i]!='\0';i++){
if(str[i]=='e'){
str[i]='x';
}
}
cout<<"the string is: "<<str<<endl;
return 0;
}
Explanation:
First, include the library iostream for using the input/output instructions.
Create the main function and declare the variables.
Then, use the cout instruction and print the message on the screen.
cin store the string enter by the user into a variable.
After that, take a for loop and if-else statement for checking the condition if the string contains the 'e', then change that alphabet to 'x'.
This process continues until the string not empty.
Finally, print the updated string.
i dont know that game but ill see if i like it and if i do ill send u my ID number ok
Answer:
import java.util.Scanner;
public class num10 {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
System.out.println("Enter the numbers to add up. enter 999 to stop");
int num = in.nextInt();
int sum = 0;
while (num!=999){
sum = sum+num;
System.out.println("Enter the next number");
num = in.nextInt();
}
System.out.println("The sum is: "+sum);
}
}
Explanation:
The application is implemented in Java
A while loop is used to continously prompt user for inputs. The condition of the while loop is while (num!=999)
When the number 999 is entered, it displays the sum which is initialized to 0
