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3 years ago

Solve for j. j/-2+7=-12 j=

1 answer:

4 0

J/-2 + 7 = -12 multiply both sides with 2

-j + 14 = -24 move -14 to the other side and change sign

-j= -24 - 14
-j = -38 and if you divide -38 with -1 you get + 38
j=38

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It takes 4 hours and 15 minutes to fly from Orlando, Florida, to Boston, Massachusetts. The distance between the two cities is 1

3241004551 [841]

Answer:

262.12mph and 419kph

Step-by-step explanation:

Given: It takes 4 hours and 15 minutes to fly from Orlando, Florida, to Boston, Massachusetts. The distance between the two cities is 1114 miles

To Find: the average speend of the plane in miles per hour, If every mile is approximately 1.6 kilometers, the speed of the airplane in kilometers per hour

Solution:

Distance between Orlando,Florida and Boston, Massachusetts $=1114$ $\text{miles}$

Time taken to cover the distance $=4\text{hours}$ and $15\text{minutes}$

We know that,

$\text{Average Speed}=\frac{\text{Total Distance}}{\text{Total time}}$

$=\frac{1114}{\frac{17}{4}}$

$=\frac{1114\times4}{17}$

$=262.12$ $\text{mph}$

It is given that,

$1\text{mile}=1.6\text{kilometer}$

therefore,

$1\text{mph}=1.6\text{kph}$

Speed Of plane in Kilometers per hours $=\text{speed in mph}\times1.6$

$419.4\text{kph}$

Speed of in miles per hour is $262.12$ $\text{mph}$ and Speed in kilometer per hour $419.4\text{kph}$

3 0

3 years ago

Marta can vacuum the house in 30 min. It takes her daughter 45 min to vacuum the house. How long would it take them if they

Mamont248 [21]

Answer:

Step-by-step explanation:

This problem is on combined work rate

given that

Marta can vacuum the house in 30 min

then her rate= 1/30

Also, her daughter will take 45 min to vacuum the house

her daughter's rate will be = 1/45

then the combined work rate is

1/30+1/45=1/T

30+45/30*45=1/T

75/1350= 1/T

1/18=1/T

This means that they will both take 18 minutes working together to vacum a house

8 0

3 years ago

Find the following measure for this figure.

marusya05 [52]

Your answer is B. 91 2/3 pi Units Squared

5 0

3 years ago

Read 2 more answers

Approximate f by a Taylor polynomial with degree n at the number a. Step 1 The Taylor polynomial with degree n = 3 is T3(x) = f(

MAVERICK [17]

Answer:

If you center the series at x=1

$T_3(x) = e^2 + 4e^2 (x-1)+10(x-1)^2 + \frac{56}{3} e^2(x-1)^3 + R(x)$

Where $R(x)$ is the error.

Step-by-step explanation:

From the information given we know that

$f(x) = e^{2x^2}$

$f'(x) = 4x e^{2x^2}$ (This comes from the chain rule )

$f^{(2)}(x) = 4e^{2x^2} (4x^2+1)$ (This comes from the chain rule and the product rule)

$f^{(3)}(x) = 16xe^{2x^2}(4x^2 + 3)$ (This comes from the chain rule and the product rule)

If you center the series at x=1 then

$T_3(x) = e^2 + 4e^2 (x-1)+10(x-1)^2 + \frac{56}{3} e^2(x-1)^3 + R(x)$

Where $R(x)$ is the error.

3 0

3 years ago

Sketch the domain D bounded by y = x^2, y = (1/2)x^2, and y=6x. Use a change of variables with the map x = uv, y = u^2 (for u ?

cluponka [151]

Under the given transformation, the Jacobian and its determinant are

$\begin{cases}x=uv\\y=u^2\end{cases}\implies J=\begin{bmatrix}v&u\\2u&0\end{bmatrix}\implies|\det J|=2u^2$

so that

$\displaystyle\iint_D\frac{\mathrm dx\,\mathrm dy}y=\iint_{D'}\frac{2u^2}{u^2}\,\mathrm du\,\mathrm dv=2\iint_{D'}\mathrm du\,\mathrm dv$

where $D'$ is the region $D$ transformed into the $u$ - $v$ plane. The remaining integral is the twice the area of $D'$ .

Now, the integral over $D$ is

$\displaystyle\iint_D\frac{\mathrm dx\,\mathrm dy}y=\left\{\int_0^6\int_{x^2/2}^{x^2}+\int_6^{12}\int_{x^2/2}^{6x}\right\}\frac{\mathrm dx\,\mathrm dy}y$

but through the given transformation, the boundary of $D'$ is the set of equations,

$\begin{array}{l}y=x^2\implies u^2=u^2v^2\implies v^2=1\implies v=\pm1\\y=\frac{x^2}2\implies u^2=\frac{u^2v^2}2\implies v^2=2\implies v=\pm\sqrt2\\y=6x\implies u^2=6uv\implies u=6v\end{array}$

We require that $u>0$ , and the last equation tells us that we would also need $v>0$ . This means $1\le v\le\sqrt2$ and $0$ , so that the integral over $D'$ is

$\displaystyle2\iint_{D'}\mathrm du\,\mathrm dv=2\int_1^{\sqrt2}\int_0^{6v}\mathrm du\,\mathrm dv=\boxed6$

4 0

3 years ago