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Usimov [2.4K]
3 years ago
11

Solve this: log798 ≈

Mathematics
2 answers:
Dafna11 [192]3 years ago
3 1

The answer is: 2.897077

ArbitrLikvidat [17]3 years ago
4 0

Answer:

The answer is 2.356

Step-by-step explanation:

Just did it on edge

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I'm not sure how to write this question. It's x-(9over3)=2 the x is separate from the 9 over 3. So basically x is subtracting fr
Artyom0805 [142]
X - 9/3 = 2

Simplify 9/3, 9/3 = 3

x - 3 = 2

Add 3 on both sides

x = 5

3 0
4 years ago
What is 20÷1÷[(10÷5)÷2]
marysya [2.9K]

Answer: 20


Step-by-step explanation:

Follow order of operations (PEMDAS)

20÷1÷[(10÷5)÷2]     Given

20÷1÷[(2)÷2]            Do 10÷5 in parenthesis

20÷1÷[(1)]                 Do (2)÷2

20÷1                        Do 1÷[(1)]

20                           Do 20÷1, and that is your answer


8 0
4 years ago
Find the straight time pay $7.60 per hour x 40 hours
gayaneshka [121]

Answer:

The straight time pay for $ 7.60 per hour and 40 work hours per week is $ 304.

Step-by-step explanation:

Let suppose that worker is suppose to work 8 hours per day, so that he must work 5 days weekly. The straight time is the suppose work time in a week, the pay is obtained after multiplying the hourly rate by the amount of hours per week. That is:

C = \left(\$\,7,60/hour\right)\cdot (40\,hours)

C = \$\,304

The straight time pay for $ 7.60 per hour and 40 work hours per week is $ 304.

5 0
3 years ago
A delivery truck is transporting boxes of two sizes: large and small. The large boxes weigh 45 pounds each, and the small boxes
shutvik [7]

Answer:

50(115-y) + 25y = 4125             [from eq2]

    5750 - 50y  + 25y = 4125           [distribute]

    5750 - 25y = 4125

     -25y = -1625

        y = 65             [divide both sides by (-25)]

There are 65 small boxes.

Put that value into either equation (now, which is easier?) to solve for x:

 x = 115 - y

 x = 115 - 65

 x = 50

 There are 50 large boxes.

- Mring0506

4 0
4 years ago
A certain car model has a mean gas mileage of 31 miles per gallon (mpg) with astandard deviation 3 mpg. A pizza delivery company
Effectus [21]

Answer:

Probability that the average mileage of the fleet is greater than 30.7 mpg is 0.7454.

Step-by-step explanation:

We are given that a certain car model has a mean gas mileage of 31 miles per gallon (mpg) with a standard deviation 3 mpg.

A pizza delivery company buys 43 of these cars.

<em>Let </em>\bar X<em> = sample average mileage of the fleet </em>

<em />

The z-score probability distribution of sample average is given by;

                   Z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \mu = mean gas mileage = 31 miles per gallon (mpg)

           \sigma = standard deviation = 3 mpg

           n = sample of cars = 43

So, probability that the average mileage of the fleet is greater than 30.7 mpg is given by = P(\bar X<em> </em>> 30.7 mpg)

     P(\bar X<em> </em>> 30.7 mpg) = P( \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } } > \frac{30.7 - 31}{\frac{3}{\sqrt{43} } } ) = P(Z > -0.66) = P(Z < 0.66)

                                                                 = 0.7454

<em>Because in z table area of P(Z > -x) is same as area of P(Z < x). Also, the above probability is calculated using z table by looking at value of x = 0.66 in the z table which have an area of 0.7454. </em>

Therefore, probability that the average mileage of the fleet is greater than 30.7 mpg is 0.7454.

5 0
3 years ago
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