Answer:
Length:28 cm
Width: 13 cm
Step-by-step explanation:
Let
x ---> the length of a rectangle picture frame
y ---> the width of a rectangle picture frame
we know that
The area of a rectangle picture frame is equal to
we have
so
----> equation A
The length of a rectangle picture frame is 2 centimeters more than twice it’s width
so
---> equation B
Solve the system by graphing
Remember that the solution is the intersection point both graphs
The solution is the point (28,13)
see the attached figure
therefore
Length:28 cm
Width: 13 cm
Answer:
2/9, 2/27
Step-by-step explanation:
54, 18, 6, 2, 2/3
Take the second term and divide by the first
18/54 = 1/3
We multiply by 1/3
Check by taking the third term and dividing by the second
6/18 = 1/3
This works
Take the last term and multiply by 1/3
2/3*1/3 = 2/9
2/9*1/3 =2/27
Now, we're assuming this is for interior angles.
the sum of all the interior angles in a polygon is
180(n - 2) n = number of sides in a polygon.
now, this is an OCTAgon, it has OCTA=8 sides, so it has a sum of its interior angles at 180( 8 - 2) --> 180(6) ---> 1080°.
now, we already know seven of those eight angles add up to 1000, so... surely you'd know what the last one is.
Answer: the probability of a student being overdrawn by more than $18.75 is 0.674
Step-by-step explanation:
Since the bank overdrafts of ASU student accounts are normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = bank overdraft of Asu students.
µ = mean
σ = standard deviation
From the information given,
µ = $21.22
σ = $5.49
We want to find the probability of a student being overdrawn by more than $18.75. It is expressed as
P(x > 18.75) = 1 - P(x ≤ 18.75)
For x = 18.75,
z = (18.75 - 21.22)/5.49 = - 0.45
Looking at the normal distribution table, the probability corresponding to the z score is 0.326
Therefore,
P(x > 18.75) = 1 - 0.326 = 0.674
Answer:
impossible
Step-by-step explanation:
There is no expression to plug x and y into
