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pochemuha
3 years ago
13

If you read can read 40 pages in 2 hours, how many pages can you read in 5 hours?

Mathematics
2 answers:
max2010maxim [7]3 years ago
5 0
40pages=2hours
40pages=2hours
40/2=20
20=1hour
40+40+20=100pages
Pavlova-9 [17]3 years ago
3 0
You can read 100 pages in 5 hours.

40 pages in 2 hours. We need to get the unit rate. In this case, we need to get the number of pages read in 1 hour.

40 pages ÷ 2 hours = 20 pages per hour.

20 pages per hours * 5 hours = 100 pages.
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Three-fifths of the sum of 9 and f
blsea [12.9K]

Answer:  \frac{3}{5} f+\frac{27}{5}

Step-by-step explanation:

Three-fifths of the sum of 9 and f is \frac{3}{5} (9+f)=\frac{27}{5} +\frac{3}{5} f=\frac{3}{5} f+\frac{27}{5}

7 0
3 years ago
Find the value of sin H rounded to the nearest hundredth, if necessary.<br> Help please
Travka [436]

Answer:

sinH ≈ 0.47

Step-by-step explanation:

sinH = \frac{opposite}{hypotenuse} = \frac{IJ}{HJ} = \frac{16}{34} ≈ 0.47 ( to the nearest hundredth )

7 0
2 years ago
2y-6x=12 what is it in slope intercept form
andrew11 [14]

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6 0
3 years ago
What is the equation of the line that passes through the points (1, 1) and (7, -5)?
xxTIMURxx [149]

Answer:

y = -1x+2

Step-by-step explanation:

(1,1)(7,-5)

y2-y1/x2-x1 = slope

-5-1/7-1 = -6/6= -1

y-y1 = slope(x-x1) // equation formula

y-1=-1(x-1)

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6 0
2 years ago
Consider f and c below. f(x, y) = x2 i + y2 j c is the arc of the parabola y = 2x2 from (−1, 2) to (1, 2) (a) find a function f
Korvikt [17]
If there is some scalar function f(x,y) such that

\nabla f(x,y)=\mathbf f(x,y)=x^2\,\mathbf i+y^2\,\mathbf j

then we want to find f such that

\dfrac{\partial f}{\partial x}=x^2\implies f(x,y)=\dfrac{x^3}3+g(y)
\dfrac{\partial f}{\partial y}=y^2=\dfrac{\mathrm dg}{\mathrm dy}\implies g(y)=\dfrac{y^3}3+C
\implies f(x,y)=\dfrac{x^3}3+\dfrac{y^3}3+C

So the vector field \mathbf f(x,y) is conservative, which means the fundamental theorem applies; the line integral of \mathbf f along any path \mathcal C parameterized by some vector-valued function \mathbf r(t) over a\le t\le b is given by

\displaystyle\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r=\int_{t=a}^{t=b}\mathbf f(\mathbf r(t))\cdot\dfrac{\mathrm d\mathbf r}{\mathrm dt}\,\mathrm dt=f(\mathbf r(b))-f(\mathbf r(a))

In this case,

\displaystyle\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r=f(1,2)-f(-1,2)=\dfrac23
5 0
3 years ago
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