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Bess [88]
2 years ago
8

Two men walk at rates of 6 miles per hour and 10 miles per hour, respectively. Simultaneously, they started from the same place

walking in opposite directions. In how many hours will they be 200 miles apart?
Mathematics
1 answer:
alina1380 [7]2 years ago
5 0

The time taken by the two men will be equal to 26 hours

<h3>What is speed?</h3>

The speed is defined as the ratio of the time distance traveled by the body to the time taken by the body to cover the distance.

here two men are walking at different speeds like

v₁=6 miles per hour

v₂=10 miles per hour

The time taken by them to separated by the distance of 100 miles each so that both of them separated by the distance of 200 miles.

t₁= {100}/{6}=16.66 hours

t₂= {100}/{10}=10 hours

total time taken will be

t₁+t₂=16.66+10=26.66 hours

To know more about Speed follow

brainly.com/question/6504879

#SPJ1

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Answer:

Given: △ABC, m∠B=90° AB=12, BC=16, BK ⊥ AC . Find: AC and BK.

Given: △ABC, m∠B=90°

Find: AC and BK.

Short leg 90 degrees Long leg Hypotenuse

AB=12 90 BC=16 AC= ?

AK = ? 90 BK = ? AB=12

AC = SQRT (AB*AB + BC*BC) = 20 [right triangle; Pythagorean Theorem]

Similar triangles:[Note: In diagram, share two angles. Therefore share three angles]

BK / 16 = AB / AC

BK / 16 = 12 / 20

BK = (3/5)16

BK = 48/5

another answer let see this

AB^2+BC^2=AC^2

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144+256=AC^2

400=AC^2

20=AC

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Step-by-step explanation:

Process

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