Time=(distance)/(speed)
speed=55 mi/hr
Total distance=440 miles
Distance covered=275 miles
remaining distance=440-275=165 miles
Time taken to cover the remaining distance will be:
time=165/55=3 hours
Total time taken to travel=440/55=8 hours
if we are to use the equation given by:
55h+275=440
time taken will be found by solving for h, thus we shall have:
55h=440-275
55h=165
h=165/55
h=3 hours
Answer: 3 hours
The answer is 200. 20*10=200
I'm pretty sure the answer is -23.4>=w
2a^2b^3(4a^2+3ab^2-ab)=?
<span>
is what I presume you actually meant. </span>
<span>
Pull out the common factors of (4a^2+3ab^2-ab) and you will get </span>
<span>
a(4a+3b^2 -b) </span>
Substitute this back into the original equation and you get
<span>
2a^2b^3[a(4a+3b^2-b)] = </span>
2a^3b^3(4a+3b^2-b) =
<span>2a^3b^3(4a-b+3b^2)
</span>
5 hundred thousand 6 thousand 7 hundred and 9
